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3 years ago

A __________ is one in which the driver's line of sight or path of travel is impeded.

Chemistry

2 answers:

luda_lava [24]3 years ago

7 0

Answer:

The correct answer is B. closed operating space

Explanation:

The closed operating space has to do with the closed zone or the closed condition that is a space condition where there is an increase in the risk level. It is not available to your vehicle’s path for traveling.

4vir4ik [10]3 years ago

6 0

The answer is B closed operating space. Hope this helps:)))

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Calcium oxide reacts with water in a combination reaction to produce calcium hydroxide. Ca) + H2O --> Ca(OH)2 In a particular

mars1129 [50]

Answer:

Percent yield = 92.5%

Explanation:

The question asks for the percent yield which can be defined as:

$\frac{actual yield}{theoretical yield} .100$

Where the actual yield is how much product was obtained, in this case 6.11 g of Ca(OH)₂, and the theoretical yield is how much product could be obtained with the given reactants theoretically, that is if the reaction would work perfectly. So we need to calculate first the theoretical yield.

1. First lets write the chemical equation reaction correctly and check that it is balanced:

CaO + H₂O → Ca(OH)₂

2. Calculate the amount of product Ca(OH)₂ that can be obtained with the given reactants (theoretical yield), which are 5.00g of CaO and excess of water. So the amount of CaO will determined how much Ca(OH)₂ we can obtained.

For this we'll use the molar ratio between CaO and Ca(OH)₂ which we see it is 1:1. For every mol of CaO we'll obtain a mol of Ca(OH)₂. So lets convert the 5.00 g of CaO to moles:

Molar Mass of CaO: 40.078 + 15.999 = 56.077 g/mol

moles of CaO = 5.00 g / 56.077 g/mol = 0.08916 moles

As we said before from the molar ratio moles of Ca(OH)₂ = moles of CaO

So the moles of Ca(OH)₂ that can be obtained are 56.077 g/mol

We need to convert this value to grams:

Molar Mass of Ca(OH)₂ = 40.078 + (15.999 + 1.008)*2 = 74.092 g/mol

Theoretical yield of Ca(OH)₂ = 0.08916 moles x 74.092 g/mol = 6.606 g

3. Calculate the percent yield:

$\frac{actual yield}{theoretical yield} .100$

Percent yield = (6.11 g / 6.606g) x 100 = 92.5 %

5 0

3 years ago

Read 2 more answers

9. Diamonds and quartz crystals look very similar but diamonds cost considerably

zheka24 [161]

Natural diamonds are made very deep within earth's surface where high temperatures and pressure exist naturally, thus making them much more difficult to obtain, and making them a more expensive option that Swarovski Crystal.

8 0

3 years ago

A sample of gas (1.3 mol) occupies __________ l at 22 Â°c and 2.5 atm.

Furkat [3]

To answer this question, you just need to put all the variable into PV = nRT formula. In this case, the pressure(P) is 2.5 atm, the number of molecule(n) is 1.3 mol, the temperature(T) is 22 celcius= 295.15 kelvin.
Then the volume should be:

PV = nRT
2.5 * V = 1.3 * 0.08206* 295.15
V= 12.59L

4 0

3 years ago

Can send me the answer plzzz

Len [333]

Answer: In balancing any chemical equations, the number of atoms of each elements on the reactant side is equals to the number of atoms of the elements on the product side.

Explanation:

Balanced Chemical equations are those equations that has the equal number of atoms of elements on both the reactants and the product sides. To ensure that the chemical equations are correctly balanced the following steps should be observed.

--> identify the elements on the reactant side and on the product side

--> identify the number of atoms of each elements.

--> multiply the number of atoms with the number that will give you a coefficient that will make both the reactant and product sides equal.

--> place the new numbers infront of the elements or compounds.

--> A final check is done to know if the equation is balanced.

From the above steps, the balanced equation of the above questions are listed below:

1.) AlBr3 + 3K ---> 3KBr + Al

2.) FeO + PdF2 --> FeF2 + PdO

3.) P4 + 6Br2 --> 4PBr3

4.) 2LiCl + Br2 --> 2LiBr + Cl2

5.) PbBr2 + 2HCl --> 2HBr + PbCl2

6.) 2CoBr3 + 3CaSO4 --> 3CaBr2 + Co2(SO4)3

7.) 2Na3P + 3CaF2 --> 6NaF + Ca3P2

8.) 2Mn + 6HI --> 3H2 + 2MnI3

9.) Li3PO4 + 3NaBr --> Na3PO4 + 3LiBr

10.) CaF2 + Li2SO4 --> CaSO4 + 2LiF

11.) 2HBr + Mg(OH)2 --> MgBr2 + 2H2O

12.) 2LiNO3 + CaBr2 --> Ca(NO3)2 + 2LiBr

13.) AgNO3 + Li --> LiNO3 +Ag

14.) Si(OH)4 + 4NaBr --> SiBr4 + 4NaOH

15.) 2NaCN + CuCO3 --> Na2CO3 + Cu(CN)2

16.) 2NH3 + H2SO4 --> (NH4)2SO4

5 0

3 years ago

Can someone help me?!!!!!

tangare [24]

Answer:

Subtract all the variables and do the opposite operation when added.

Explanation:

4 0

3 years ago