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ale4655 [162]
3 years ago
7

A big box of sausages (30 kg) are lifted from the ground to the top shelf of the freezer. If the box is lifted at a constant spe

ed, a distance of 1.75 m, what work is done by gravity?
Physics
1 answer:
morpeh [17]3 years ago
4 0

Answer:

The work done by gravity moving the box up is -514.5 Joules.

Explanation:

The gravity acts in the direction of the displacement, which in this case is negative (ground - top shelf), and so the resulting work is negative. The work is calculated as:

W_g = mg\Delta h = 30kg\cdot 9.8\frac{m}{s^2}\cdot(0-1.75)m=-514.5J

The work done by gravity moving the box up is -514.5 Joules.


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Which of the following is a FALSE statement? A. Heat moves through solids by conduction. B. Molecules move faster in warmer subs
matrenka [14]
C is the FALSE statement.
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A certain radio wave has a frequency of 2.0 x 10^6 Hz. What is its wavelength?
evablogger [386]

<span>1.    </span>Electromagnetic radiation are represented in waves. Each type of wave has a certain shape and length. The distance between two peaks in a wave is called the wavelength. This value is equal to the speed of light divided by the frequency.

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4 years ago
How much work (MJ) must a car produce to drive 125 miles if an average force of 306 N must be maintained to overcome friction?
baherus [9]

Answer:

The right solution is "61.557 MJ". A further explanation is given below.

Explanation:

The given values are:

Force,

F = 306 N

Drive,

D = 125 miles,

i.e.,

  = 201168

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As we know,

The work done will be:

= F\times S

On substituting the given values, we get

= 306\times 201168

= 61557408 \ J

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= 61.557\times 10^6 \ J

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6 0
3 years ago
A potential difference of 3.27 nV is set up across a 2.16 cm length of copper wire that has a radius of 2.33 mm. How much charge
miskamm [114]

Answer:

Charge = 4.9096 x 10⁻⁷ C

Explanation:

First, we find the resistance of the copper wire.

R = ρL/A

where,

R = resistance = ?

ρ = resistivity of copper = 1.69 x 10⁻⁸ Ω.m

L = Length of wire = 2.16 cm = 0.0216 m

A = Cross-sectional area of wire = πr² = π(0.00233 m)² = 1.7 x 10⁻⁵ m²

Therefore,

R = (1.69 x 10⁻⁸ Ω.m)(0.0216 m)/(1.7 x 10⁻⁵ m²)

R = 2.14 x 10⁻⁵ Ω

Now, we find the current from Ohm's Law:

V =IR

I = V/R

I = 3.27 x 10⁻⁹ V/2.14 x 10⁻⁵ Ω

I = 1.52 x 10⁻⁴ A

Now, for the charge:

I = Charge/Time

Charge = (I)(Time)

Charge = (1.52 x 10⁻⁴ A)(3.23 x 10⁻³ s)

<u>Charge = 4.9096 x 10⁻⁷ C</u>

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4 years ago
Why is Carbon Tetrahydride a covalent bond? plzzz helpppp!!!!!!​
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Answer:

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