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BlackZzzverrR [31]
3 years ago
12

Suppose we wrap a string around the surface of a uniform cylinder of radius 38.0 cm that is supported by an axle passing through

its center. This cylinder rotates without friction and we tie a mass to the end of the string and let it fall under the influence of gravity. As the weight falls, we measure the constant acceleration of the falling mass to be 9.0 m/s2. Find the angular acceleration that the cylinder will experience under these conditions. (Assume the positive direction is the initial direction of rotation of the cylinder. Indicate the direction with the sign of your answer.)
Physics
1 answer:
liraira [26]3 years ago
4 0

Answer:

Angular acceleration = 23.68 rad / s²

Explanation:

Given that,

acceleration = 9m/s²

Therefore acceleration of string is 9m/s²

since string is constant in length

cylinder of radius 38.0 cm = 0.38m

Angular acceleration = a / r

Angular acceleration = 9 / 0.38

                                   = 23.68 rad / s²

Angular acceleration = 23.68 rad / s²

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True False Suppose I have a resistor of some resistance R. If I were to double the length and double the cross-sectional area of
skad [1K]

Explanation:

The resistance of a wire is given by :

R=\rho\dfrac{l}{A}

Where

\rho is the resistivity of the wire

l = initial length of the wire

A = initial area of cross section

If length and the area of cross section of the wire is doubled then new length is l' and A', l' = 2 l and A' = 2 A

So, new resistance of the wire is given by :

R'=\rho\dfrac{l'}{A'}

R'=\rho\dfrac{l}{A}

R' = R

So, the resistance of the wire remains the same on doubling the length and the area of wire.

4 0
3 years ago
Two identical loudspeakers are driven in phase by a common oscillator at 750 Hz and face each other at a distance of 1.24 m. Loc
Juli2301 [7.4K]

Answer:

0.2286  m,  0.686 m and  1,143 m

therefore we see that there is respect even where the intensity is minimal

Explanation:

Destructive interference to the two speakers is described by the expression

       Δr = (2n +1) λ/2

where r is the distance,  λ the wavelength and n an integer indicating the order of the interference

let's locate the origin on the left speaker

let's find the wavelength with the equation

        v =  λ f

         λ = v / f

we substitute

      Δr = (2n + 1) v / 2f

let's calculate for difference values ​​of n

     Δr = (2n +1) 343/(2 750)

     Δr = (2n + 1) 0.2286

we locate the different values ​​for a minimum of interim

    n     Δr (m)

     0    0.2286

     1     0.686

     2    1,143

therefore we see that there is respect even where the intensity is minimal

6 0
3 years ago
Rocket-powered sleds are used to test the human response to acceleration. If a rocket-powered sled is accelerated to a speed of
Arlecino [84]

Answer:

a=242.62\ m/s^2

Explanation:

The rocket-powered sled is accelerated to a speed of 444 m/s in 1.83 seconds.

We need to find the acceleration of the rocket. Initially it was at rest, u = 0

Acceleration = rate of change of velocity

a=\dfrac{444\ m/s}{1.83\ s}\\\\a=242.62\ m/s^2

So, the acceleration of the rocket is 242.62\ m/s^2.

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3 years ago
Why is it impossible for us to observe any furthur than 13.7 billion light years in the universe??
Burka [1]
Because made it like that
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The current theory of the structure of the Earth, called plate tectonics, tells us what the continents are in constant motion. A
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A) We need to first determine the volume of the continent and then mass would be = Volume x density

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= 817 x 10^15 cubic meter x 2720kg/m^3

= 2.2 x 10^21 Kg

B)

Kinetic Energy = ½mV²

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= 2340 J

3 0
4 years ago
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