Answer:
So then we will have at least 75% of the data within two deviations from the mean 
.
So then the interval would be (97.14, 99.5)
Explanation:
Previous concepts
Chebyshev’s rule is appropriate for any distribution. "Chebyshev’s inequality applies to all distributions, regardless of shape". And is useful since provides a "minimum percentage of the observations that lies within k standard deviations of the mean. "
If k = 2, at least 3/4 of the measurements lie within 2 standard deviations to within the mean.
And the general formula is (1-1/k^2) represent the fraction of the data within the mean .
Solution to the problem
For this case we want to find the percentage of data that would be at least within two deviations from the mean so for this case the value of k =2 and if we replace we got:
So then we will have at least 75% of the data within two deviations from the mean .
For the other part we have the mean and deviation provided 
the interval would be:
So then the interval would be (97.14, 99.5)
The answer is B. Hope this helps
Answer:
8.67807 N
34.7123 N
Explanation:
m = Mass of shark = 92 kg
= Density of seawater = 1030 kg/m³
= Density of freshwater = 1000 kg/m³
= Density of shark = 1040 kg/m³
g = Acceleration due to gravity = 9.81 m/s²
Net force on the fin is (seawater)
The lift force required in seawater is 8.67807 N
Net force on the fin is (freshwater)
The lift force required in a river is 34.7123 N
Answer:
Balanced forces do not result in any change in motion. forces: forces applied to an object in opposite directions that are not equal in size. Unbalanced forces result in a change in motion.
Explanation:
Answer:
W = 1222.4 J = 1.22 KJ
Explanation:
The work done on an object is the product of the force applied on it and the displacement it covers as a result of this force. It must be noted that the component of displacement in the direction of force should only be used. Hence, the work can be calculated as:
W = F d Cosθ
where,
W = Work Done = ?
F = Force Applied = 64 N
d = Distance Covered by Box = 19.1 m
θ = Angle between force and displacement = 0°
Therefore,
W = (64 N)(19.1 m)Cos 0°
<u>W = 1222.4 J = 1.22 KJ</u>
