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Tresset [83]
3 years ago
13

What is the average linear (seepage) velocity of water in an aquifer with a hydraulic conductivity of 6.9 x 10-4 m/s and porosit

y of 30% if the hydraulic gradient is 0.0014? a. 0.28 m/d b. 3.2 m/d c. 0.08 m/d d. 0.003 m/d
Engineering
1 answer:
jeka943 years ago
4 0

Answer:

a. 0.28

Explanation:

Given that

porosity =30%

hydraulic gradient = 0.0014

hydraulic conductivity = 6.9 x 10⁻4 m/s

We know that average linear velocity given as

v=\dfrac{K}{n_e}\dfrac{dh}{dl}

v=\dfrac{6.9\times 10^{-4}}{0.3}\times0.0014\ m/s

v=3.22\times 10^{-6}\ m/s

The velocity in m/d      ( 1 m/s =86400 m/d)

v= 0.27 m/d

So the nearest answer is 'a'.

a. 0.28

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A cylindrical insulation for a steam pipe has an inside radius rt = 6 cm, outside radius r0 = 8 cm, and a thermal conductivity k
goldfiish [28.3K]

Answer:

heat loss per 1-m length of this insulation is 4368.145 W

Explanation:

given data

inside radius r1 = 6 cm

outside radius r2 = 8 cm

thermal conductivity k = 0.5 W/m°C

inside temperature t1 = 430°C

outside temperature t2 = 30°C

to find out

Determine the heat loss per 1-m length of this insulation

solution

we know thermal resistance formula for cylinder that is express as

Rth = \frac{ln\frac{r2}{r1}}{2 \pi *k * L}   .................1

here r1 is inside radius and r2 is outside radius L is length and k is thermal conductivity

so

heat loss is change in temperature divide thermal resistance

Q = \frac{t1- t2}{\frac{ln\frac{r2}{r1}}{2 \pi *k * L}}

Q = \frac{(430-30)*(2 \pi * 0.5 * 1}{ln\frac{8}{6} }

Q = 4368.145 W

so heat loss per 1-m length of this insulation is 4368.145 W

4 0
3 years ago
A slender rod AB, of weight W, is attached to blocks A and B, which move freely in the guides shown. The blocks are connected by
gregori [183]

Answer:

(a) T = W/2(1-tanθ)  (b) 39.81°

Explanation:

(a) The equation for tension (T) can be derived by considering the summation of moment in the clockwise direction. Thus:

Summation of moment in clockwise direction is equivalent to zero. Therefore,

T*l*(sinθ) + W*(l/2)*cosθ - T*l*cosθ = 0

T*l*(cosθ - sinθ) = W*(l/2)*cosθ

T = W*cosθ/2(cosθ - sinθ)

Dividing both the numerator and denominator by cosθ, we have:

T = [W*cosθ/cosθ]/2[(cosθ - sinθ)/cosθ] = W/2(1-tanθ)

(b) If T = 3W, then:

3W = W/2(1-tanθ),

Further simplification and rearrangement lead to:

1 - tanθ = 1/6

tanθ = 1 - (1/6) = 5/6

θ = tan^(-1) 5/6 = 39.81°

8 0
3 years ago
The B-pillar may also be called the:
slega [8]

Answer:

if you're talking about the car b-post, the answer is "posts"

Explanation:

looked it up

6 0
3 years ago
For some transformation having kinetics that obey the Avrami equation, the parameter n is known to have a value of 1.7. If, afte
luda_lava [24]

Answer:

It would take approximately 305 s to go to 99% completion

Explanation:

Given that:

y = 50% = 0.5

n = 1.7

t = 100 s

We need to first find the parameter k from the equation below.

exp(-kt^n)=1-y

taking the natural logarithm of both sides:

-kt^n=ln(1-y)\\kt^n=-ln(1-y)\\k=-\frac{ln(1-y)}{t^n}

Substituting values:

k=-\frac{ln(1-y)}{t^n}= -\frac{ln(1-0.5)}{100^1.7} = 2.76*10^{-4}

Also

t^n=-\frac{ln(1-y)}{k}\\t=\sqrt[n]{-\frac{ln(1-y)}{k}}

Substituting values and y = 99% = 0.99

t=\sqrt[n]{-\frac{ln(1-y)}{k}}=\sqrt[1.7]{-\frac{ln(1-0.99)}{2.76*10^{-4}}}=304.6s

∴ t ≅ 305 s

It would take approximately 305 s to go to 99% completion

8 0
3 years ago
Read 2 more answers
The role of civil and structural engineer is to produce buildings for
Alinara [238K]
So I’m thinking C because they both have a lot to do with design here is my evidence. Structural engineering is a component of civil engineering which focuses on the design and development of infrastructures such as bridges, skyscrapers, dams. Civil engineering is a professional engineering discipline that deals with the design, construction, and maintenance of the physical and naturally built environment. I may be wrong but hope this helped!
3 0
3 years ago
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