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3 years ago

Bore = 3"

Engineering

2 answers:

Grace [21]3 years ago

5 0

I need help my self lol XD

klemol [59]3 years ago

5 0

The answers is ( c)
I took the test my self

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A company that produces footballs uses a proprietary mixture of ideal gases to inflate their footballs. If the temperature of 23

Arte-miy333 [17]

Answer:

35 g/mol

Explanation:

Convert to SI units.

465 R × 5/9 = 258.3 K

Assuming the pressure is absolute pressure:

135 psi × (101.3 kPa / 14.7 psi) = 930.3 kPa

Ideal gas law:

PV = nRT

(930.3 kPa) (15 L) = n (8.314 kPa L / mol / K) (258.3 K)

n = 6.50 mol

The molar mass is therefore:

230 g / 6.50 mol = 35.4 g/mol

Rounded to two significant figures, the molar mass is 35 g/mol.

5 0

2 years ago

Cómo se llama el componente, que permite abrir o cerrar un circuito eléctrico

Korolek [52]

Creo haber leído sobre esto..Un “interruptor” yo diría

5 0

2 years ago

Refrigerant-134a enters the expansion valve of a refrigeration system at 120 psia as a saturated liquid and leaves at 20 psia. D

Shkiper50 [21]

Solution :

$P_1 = 120 \ psia$

$P_2 = 20 \ psia$

Using the data table for refrigerant-134a at P = 120 psia

$h_1=h_f=40.8365 \ Btu/lbm$

$u_1=u_f=40.5485 \ Btu/lbm$

$T_{sat}=87.745^\circ F$

∴ $h_2=h_1=40.8365 \ Btu/lbm$

For pressure, P = 20 psia

$h_{2f} = 11.445 \ Btu/lbm$

$h_{2g} = 102.73 \ Btu/lbm$

$u_{2f} = 11.401 \ Btu/lbm$

$u_{2g} = 94.3 \ Btu/lbm$

$T_2=T_{sat}=-2.43^\circ F$

Change in temperature, $\Delta T = T_2-T_1$

$\Delta T = -2.43-87.745$

$\Delta T=-90.175^\circ F$

Now we find the quality,

$h_2=h_f+x_2(h_g-h_f)$

$40.8365=11.445+x_2(91.282)$

$x_2=0.32198$

The final energy,

$u_2=u_f+x_2.u_{fg}$

$=11.401+0.32198(82.898)$

$=38.09297 \ Btu/lbm$

Change in internal energy

$\Delta u= u_2-u_1$

= 38.09297-40.5485

= -2.4556

5 0

2 years ago

You are designing the access control policies for a Web-based retail store. Customers access the store via the Web, browse produ

PolarNik [594]

Answer:

Object-Oriented Software Engineering Using UML, Patterns, and Java, 3e, shows readers how to use both the principles of software engineering and the practices of various object-oriented tools, processes, and products.

3 0

2 years ago

2. A well of 0.1 m radius is installed in the aquifer of the preceding exercise and is pumped at a rate averaging 80 liter/min.

hodyreva [135]

Question:

The question is not complete. See the complete question and the answer below.

A well that pumps at a constant rate of 0.5m3/s fully penetrates a confined aquifer of 34 m thickness. After a long period of pumping, near steady state conditions, the measured drawdowns at two observation wells 50m and 100m from the pumping well are 0.9 and 0.4 m respectively. (a) Calculate the hydraulic conductivity and transmissivity of the aquifer (b) estimate the radius of influence of the pumping well, and (c) calculate the expected drawdown in the pumping well if the radius of the well is 0.4m.

Answer:

T = 0.11029m²/sec

Radius of influence = 93.304m

expected drawdown = 3.9336m

Explanation:

See the attached file for the explanation.

8 0

3 years ago