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Nastasia [14]
3 years ago
13

Bore = 3"

Engineering
2 answers:
Grace [21]3 years ago
5 0
I need help my self lol XD
klemol [59]3 years ago
5 0
The answers is ( c)
I took the test my self
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Calculate the load, PP, that would cause AA to be displaced 0.01 inches to the right. The wires ABAB and ACAC are A36 steel and
Nataly [62]

Answer:

P = 4.745 kips

Explanation:

Given

ΔL = 0.01 in

E = 29000 KSI

D = 1/2 in  

LAB = LAC = L = 12 in

We get the area as follows

A = π*D²/4 = π*(1/2 in)²/4 = (π/16) in²

Then we use the formula

ΔL = P*L/(A*E)

For AB:

ΔL(AB) = PAB*L/(A*E) = PAB*12 in/((π/16) in²*29*10⁶ PSI)

⇒  ΔL(AB) = (2.107*10⁻⁶ in/lbf)*PAB

For AC:

ΔL(AC) = PAC*L/(A*E) = PAC*12 in/((π/16) in²*29*10⁶ PSI)

⇒  ΔL(AC) = (2.107*10⁻⁶ in/lbf)*PAC

Now, we use the condition

ΔL = ΔL(AB)ₓ + ΔL(AC)ₓ = ΔL(AB)*Cos 30° + ΔL(AC)*Cos 30° = 0.01 in

⇒  ΔL = (2.107*10⁻⁶ in/lbf)*PAB*Cos 30°+(2.107*10⁻⁶ in/lbf)*PAC*Cos 30°= 0.01 in

Knowing that   PAB*Cos 30°+PAC*Cos 30° = P

we have

(2.107*10⁻⁶ in/lbf)*P = 0.01 in

⇒  P = 4745.11 lb = 4.745 kips

The pic shown can help to understand the question.

5 0
3 years ago
When the Moon is in the position shown, how would the Moon look to an observer on the North Pole?
kirill115 [55]

Answer:

cant see the moon sorry dude

5 0
3 years ago
How is air pressure affected by the shape of an aircraft wing
oksano4ka [1.4K]

Answer:

Airplanes' wings are curved on top and flatter on the bottom. That shape makes air flow over the top faster than under the bottom. As a result, less air pressure is on top of the wing. This lower pressure makes the wing, and the airplane it's attached to, move up.

Explanation:

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3 years ago
What is the thermal efficiency of this regeneration cycle in terms of enthalpies and fractions of total flow?
irga5000 [103]

Answer:

\eta =\dfrac{(h_3-h_4)-(h_2-h_1)}{(h_3-h_5)}

Explanation:

generally regeneration of cycle is used in the case of gas turbine. due to regeneration efficiency of turbine is increased but there is no effect on the on the net work out put of turbine.Actually in regeneration net heta input is decreases that is why total efficiency  increase.

 Now from T-S diagram

    W_{net}=W_{out}-W_{in}

   W_{net}=(h_3-h_4)-(h_2-h_1)

  Q_{in}=h_3-h_5

  Due to generation (h_5-h_2) amount of energy has been saved.

  Q_{generation}=Q_{saved}

So efficiency of cycle \eta =\frac{W_{net}}{Q_{in}}

  \eta =\dfrac{(h_3-h_4)-(h_2-h_1)}{(h_3-h_5)}

Effectiveness of re-generator

  \varepsilon =\dfrac{(h_5-h_2)}{(h_4-h_2)}

So the efficiency of regenerative cycle

\eta =\dfrac{(h_3-h_4)-(h_2-h_1)}{(h_3-h_5)}

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3 years ago
It's not a slot machine
scoundrel [369]
Maybe it’s a vending machine, I’m confused too
5 0
3 years ago
Read 2 more answers
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