Answer:
coupling is in tension
Force = -244.81 N
Explanation:
Diameter of Hose ( D1 ) = 35 mm
Diameter of nozzle ( D2 ) = 25 mm
water gage pressure in hose = 510 kPa
stream leaving the nozzle is uniform
exit speed and pressure = 32 m/s and atmospheric
<u>Determine the force transmitted by the coupling between the nozzle and hose </u>
attached below is the remaining part of the detailed solution
Inlet velocity ( V1 ) = V2 ( D2/D1 )^2
= 32 ( 25 / 35 )^2
= 16.33 m/s
The exit temperature is 586.18K and compressor input power is 14973.53kW
Data;
The exit temperature of the gas can be calculated isentropically as
Let's substitute the values into the formula
The exit temperature is 586.18K
<h3>The Compressor input power</h3>The compressor input power is calculated as
The compressor input power is 14973.53kW
Learn more on exit temperature and compressor input power here;
Answer:
The convective coefficient is 37.3 W/m²K.
Explanation:
Use Newton’s law of cooling to determine the heat transfer coefficient. Assume there is no heat transfer from the ends of electric resistor. Heat is transferred from the resistor curved surface.
Step1
Given:
Diameter of the resistor is 2 cm.
Length of the resistor is 16 cm.
Current is 5 amp.
Voltage is 6 volts.
Resistor temperature is 100°C.
Room air temperature is 20°C.
Step2
Electric power from the resistor is transferred to heat and this heat is transferred to the environment by means of convection.
Power of resistor is calculated as follows:
P=VI
P= 30 watts.
Step3
Newton’s law of cooling is expressed as follows:
Here, h is the convection heat coefficient and is the exposed surface area of the resistor.
Substitute the values as follows:
h = 37.3 W/m²K.
Thus, the convective coefficient is 37.3 W/m²K.