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FrozenT [24]
3 years ago
5

A certain light truck can go around a flat curve having a radius of 150 m with a maximum speed of 28.0 m/s. With what maximum sp

eed can it go around a curve having a radius of 73.0 m?
Physics
1 answer:
Dima020 [189]3 years ago
5 0

Given Information:  

Radius = r₁ = 150 m

Radius = r₂ = 73 m

Maximum speed = v₁ = 28.0 m/s

Required Information:  

Maximum speed = v₂ = ?

Answer:

Maximum speed v₂ = 19.53 m/s

Explanation:

The maximum acceleration of the truck is

a = v²₁/r₁

a = 28²/150

a = 5.226 m/s²

Now if we change the radius to r₂ = 73 m

Then the maximum speed of the truck is

v₂ = √a*r₂

v₂ = √5.226*73

v₂ = 19.53 m/s

So the speed of the truck is decreased when the radius of curve is decreased.

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speed of the car is given on the road

v = 22 m/s

reaction time is given as

t = 0.50 s

now we can find the distance that it will move during this reaction time

d_1 = 22* 0.50 = 11 m

now the deceleration of the car is 10 m/s^2

so the distance that it will move before stop is given by

v_f^2 - v_i^2 = 2 a d

0^2 - 22^2 = 2*(-10)*d

d = 24.2 m

so the total distance that it require to stop is given as

d = 24.2 + 11 = 35.2 m

while the deer is standing at distance 38 m

so the car will stop 2.8 m before the position of deer


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3 years ago
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Answer:

(a) has the highest frequency

Explanation:

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Whereby this formula shows us that energy of a photon is directly proportional to its frequency

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Which of The following is the best example of water changing from a liquid to gas
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Explanation:

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Two trains are blowing their whistles. The first train is stationary, and the
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A 0.12 kg body undergoes simple harmonic motion of amplitude 8.5 cm and period 0.20 s. (a) What is themagnitude of the maximum f
Neporo4naja [7]

Answer:

a)F=698.83 N

b)K=8221.56 N/m

Explanation:

Given that

mass ,m = 0.12 kg

Amplitude ,A= 8.5 cm

time period ,T = 0.2 s

We know that

T=\dfrac{2\pi}{\omega}

{\omega}=\dfrac{2\pi }{0.2}\ rad/s

{\omega}=31.41\ rad/s

We know that

{\omega}^2=m\ K

K=Spring constant

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K=\dfrac{31.41^2}{0.12}\ N/m

K=8221.56 N/m

The maximum force F

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a)F=698.83 N

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