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Answer:
appx. 1.07 moles
Explanation:
175g of molecule Ca(NO3)2
To find the # of moles, use stoichoimetry.
1. We need the molar mass of Ca(NO3)2.
Ca mass: 40.08 g
NO3 mass: N + 3(O) --> 14.01 + 3(16.00) --> 62.01
Molar mass = Ca + 2(NO3) --> 40.08 + 2(62.01) --> 164.1 g
2. write out the calculation
175g Ca(NO3)2 * (1 mole Ca(NO3)2)/(molar mass of Ca(NO3)2)
175 g Ca(NO3)2 * (1 mole Ca(NO3)2)/(164.1 g Ca(NO3)2)
The g units cancel out and we're left with moles.
Simply perform the calculation now: 175*1/164.1 ≅1.07 moles
Answer: There are 0.056 moles present in 3.45 g of 
.
Explanation:
Given : Mass = 3.45 g
Moles is the mass of substance divided by its molar mass.
Hence, moles of (molar mass = 61.98 g/mol) is as follows.
Thus, we can conclude that there are 0.056 moles present in 3.45 g of .
