Discuss and Implement the Price Adjustment Strategies in the current market. Apply each strategy with 3 examples along with the
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After ion exchange with zeolite in water filter to remove calcium by substitute natrium ion with calcium ion, the weight of zeolite become 1.9578 kg.
ion exchange calculation can be done by using basic stoichiometry if we know how the reaction of the ion exchange. In this case where zeolite with natrium ion will be exchanged with calcium. The reaction of exchange will be like this:
⇒
Calculate the molecule weight of both zeolite
Atomic weight data:
Na = 23 gram/mole
Si = 28 gram/mole
Al = 27 gram/mole
O = 16 gram/mole
Ca = 40 gram/mole
Molecule weight
= 142 gram/mole
= 278 gram/mole
Calculate mole from 2kg of zeolite with natrium :
2000 gram/ 142 = 14.0845 mole
Based on the stoichiometry, we got the mole of zeolite with calcium:
14.0845 mole x 1/2 = 7.0423 mole
Weight of zeolite after the ion exchanged with calcium:
7.0423 mole x 278 = 1957.8 gram = 1.9578 kg
Learn more about ion exchange here: brainly.com/question/28203551
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<u>Answer:</u> The final temperature of the mixture is 51.49°C
<u>Explanation:</u>
When two samples of water are mixed, the heat released by the water at high temperature will be equal to the amount of heat absorbed by water at low temperature
The equation used to calculate heat released or absorbed follows:
......(1)
where,
q = heat absorbed or released
= mass of water at high temperature = 140 g (Density of water = 1.00 g/mL)
= mass of water at low temperature = 230 g
= final temperature = ?°C
= initial temperature of water at high temperature = 95.00°C
= initial temperature of water at low temperature = 25.00°C
c = specific heat of water= 4.186 J/g°C
Putting values in equation 1, we get:
Hence, the final temperature of the mixture is 51.49°C