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Len [333]
3 years ago
11

A sample of a compound made entirely from copper and oxygen was found to have a total mass of 0.1431g The mass of the copper In

the compound was found to be 0.1271g. Calculate the number of moles of copper in the sample.
Chemistry
1 answer:
Ket [755]3 years ago
5 0
Number of moles of Cu in 63.546 g is 1 mole

1 / 63.546 = 0.0157366317

Number of moles in 1 g of Cu is 0.0157366317

0.0157366317 x 0.1431

0.002251912 moles will be the answer
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What is Heterogeneous? And an example. What is Homogeneous? And an example. I just need those, thanks
Sedbober [7]
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7 0
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Arsenic does not have any valence electrons in the 3D orbital because​
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3d orbital is completely filled.

Explanation:

5 0
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silver has an atomic mass of 107.868 amu. silver has two common isotopes. one of the isotopes has a mass of 106.906 amu and a re
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A. The abundance of the 2nd isotope is 48.119%

B. The mass of the 2nd isotope is 108.905 amu

Let the 1st isotope be A

Let the 2nd isotope be B

A. Determination of the abundance of the 2nd isotope

Abundance of isotope A = 51.881%.

<h3>Abundance of isotope B =? </h3>

Abundance of B = 100 – A

Abundance of B = 100 – 51.881

<h3>Abundance of B = 48.119%</h3>

B. Determination of the mass of the 2nd isotope

Atomic mass of silver = 107.868 amu.

Mass of 1st isotope (A) = 106.906 amu

Abundance of isotope A (A%) = 51.881%.

Abundance of isotope B (B%) = 48.119%

<h3>Mass of 2nd isotope (B) =? </h3>

atomic \: mass =  \frac{mass \: of \:A \times \:A\%}{100}  + \frac{mass \: of \:B \times \:B\%}{100} \\  \\ 107.868 = \frac{106.906\times \ \: 51.881}{100}  + \frac{mass \: of \:B \times \:48.119}{100} \\  \\ 107.868 = \: 55.464 + 0.48119 \times mass \: of \:B  \\  \\  collect \: like \: terms \\  \\ 0.48119 \times mass \: of \:B  = 107.868  - 55.464  \\  \\ divide \: both \: side \: by \: 0.48119 \\  \\ mass \: of \:B  = \frac{107.868  - 55.464 }{0.48119}  \\  \\ mass \: of \:B  =108.905 \: amu \\  \\

Therefore, the mass of the 2nd isotope is 108.905 amu

Learn more: brainly.com/question/7955048

6 0
2 years ago
How many liters are in 3.45 moles of oxygen gas at STP?
just olya [345]

Answer:

22.4L of one mole of any gas

or you can use PV=nRT

3.45*22.4=77.28

Explanation:

5 0
3 years ago
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