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e-lub [12.9K]
4 years ago
7

Why-does-the-energy-of-a-sound-wave-decrease-over-time

Physics
1 answer:
KengaRu [80]4 years ago
7 0
The sound wave never actually loses energy, the bulk of energy it had at the beginning of the sound, is spread out into a sphere, making it decrease in amplitude and frequency. 
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A sound wave has a speed of 330m/s and a wavelength of 0.372 m. what is the frequency of the wave?
Alja [10]

Answer:

887.1Hz

Explanation:

Given parameters:

Speed of sound wave  = 330m/s

Wavelength  = 0.372m

Unknown:

Frequency  = ?

Solution:

To solve this problem, we use the expression below:

             Speed  = Frequency x wavelength

            330  = Frequency x 0.372

   Frequency  = 887.1Hz

5 0
3 years ago
It takes fifteen minutes to complete a drilling operation using a lathe. the duration of this operation is known as _____ time.
dalvyx [7]
I think the correct answer would be processing time. The time of fifteen minutes describes how long the whole operation was done or how long is the whole processing of drilling. Hope this answers the question. Have a nice day.
8 0
4 years ago
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OLga [1]

Answer:

The chemical formula for zinc (III) phosphide is Zn3P2

3 0
3 years ago
Lower chamber of Congress has how many members?
Molodets [167]

Answer:435 Representatives

Explanation:The lower chamber of Congress, in which the number of representatives per state is determined by the state's population, with 435 Representatives total. Members of the House of Representatives serve two-year terms, so they are up for reelection every two years.

6 0
2 years ago
Hooke's law describes a certain light spring of unstretched length 33.6 cm. when one end is attached to the top of a doorframe a
masha68 [24]
Missing question: "What is the spring's constant?"

Solution:
The object of mass m=6.89 kg exerts a force on the spring equal to its weight:
F=mg=(6.89 kg)(9.81 m/s^2)=67.6 N
When the object is attached to the spring, the displacement of the spring with respect to its equilibrium position is
\Delta x=43.2 cm-33.6 cm=9.6 cm=0.096 m
And by using Hook's law, we can find the constant of the spring:
k= \frac{F}{\Delta x}= \frac{67.6 N}{0.096 m}=704.2 N/m
4 0
4 years ago
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