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e-lub [12.9K]
3 years ago
7

Why-does-the-energy-of-a-sound-wave-decrease-over-time

Physics
1 answer:
KengaRu [80]3 years ago
7 0
The sound wave never actually loses energy, the bulk of energy it had at the beginning of the sound, is spread out into a sphere, making it decrease in amplitude and frequency. 
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an object is producing a sound that has a wavelength in air of 2.69m. If the speed of sound in air is 346m/s, what is the freque
Misha Larkins [42]

Answer:

129.74 Hz

Explanation:

Given:

Wave velocity ( v ) = 346 m / sec

wavelength ( λ ) = 2.69 m

We have to calculate Frequency ( f ) :

We know:

v = λ / t [ f = 1 / t ]

v = λ f

= > f = v / λ

Putting values here we get:

= > f = 346 / 2.69 Hz

= > f = 34600 / 269 Hz

= > f = 129.74 Hz

Hence, frequency of sound is 129.74 Hz.

5 0
3 years ago
PLEASE HELP, LOOK AT PHOTO PLZ!!!
PIT_PIT [208]

Answer:

a) 17 km

b) 9 km

Explanation:

The distance is the length of the path.

A to C: 5 km

B to C: 4 km

C to B: 4 km

B to C: 4 km

Total distance = 5 km + 4 km + 4 km + 4 km = 17 km

Displacement is the difference between the starting point and ending point.

Displacement = 9 km − 0 km = 9 km

3 0
3 years ago
For which group of people might brain-powered cars allow the greatest increase in mobility?
dolphi86 [110]
Brain-powered cars?
The answer would be people who lack motor skills in their legs.
8 0
3 years ago
Read 2 more answers
Two acrobats flying through the air grab and hold onto each other in midair as part of a circus act.One acrobat has a mass of 60
earnstyle [38]

Answer:

1.36m/s

Explanation:

We are given that

Mass of one acrobat,m_1=60 kg

Mass of another acrobat,m_2=50 kg

v_2=-3 m/s

v_1=5 m/s

We have to find their  velocity immediately after they grab  onto each other.

The collision between two acrobat is inelastic

According to law of conservation of momentum

m_1v_1+m_2v_2=(m_1+m_2)V

Substitute the values

60\times 5+50(-3)=(60+50)V

300-150=110V

V=\frac{300-150}{110}=1.36m/s

4 0
3 years ago
A spherical steel ball bearing has a diameter of 2.540 cm at 20.00°C. (Assume the coefficient of linear expansion for steel is 1
shusha [124]

Answer:

(a) 2.542 cm

(b) 272.7°C

Explanation:

diameter, d = 2.540 cm

T1 = 20°C

α = 11 x 10^-6 /°C

(a) Let d' be the diameter.

T2 = 87°C

Use he formula for the areal expansion

A' = A ( 1 + βΔT)

where, β is the coefficient of areal expansion and ΔT is teh rise in temperature, A' be the area at high temperature and A be the area at low temperature.

β = 2 α = 2 x 11 x 106-6 = 22 x 10^-6 /°C

So,

\frac{\pi D'^{2}}{4}=\frac{\pi D^{2}}{4}\left ( 1+\beta \Delta T \right )

D'^2 = 2.54^2 ( 1 + 22 x 10^-6 x 67)

D' = 2.542 cm

(b) Let the change in temperature is ΔT.

Use the formula for the volumetric expansion

ΔV = V x γ x ΔT

Where, γ = 3 x α = 3 x 11 x 10^-6 = 33 x 10^-6 /°C

0.9/100 = 33 x 10^-6 x ΔT

ΔT = 272.7°C

6 0
3 years ago
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