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NeTakaya
3 years ago
5

What is the kinetic energy of a 2600kg car traveling 24m/s?

Physics
1 answer:
Shalnov [3]3 years ago
5 0

Answer:

748.8 kJ

Explanation:

Kinetic energy is given by

KE=\frac {mv^{2}}{2} where m is the mass of the body, v is the velocity

Substituting 2600 Kg for m and 24 m/s for velocity

KE=\frac {2600 Kg\times 24^{2} m/s}{2}=748800 J=748.8 kJ

Therefore, kinetic energy is 748.8 kJ

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ahrayia [7]
B. velocity is the speed in any given direction.
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An inexperienced researcher runs an experiment and sets his alpha level at .40 because he can't wait to get his firstsignificant
GuDViN [60]

A potential problem is that you are willing to accept a <u>5% </u>chance of being wrong if you reject the null hypothesis.

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The smaller the value of α the more difficult it is to reject the null hypothesis. Therefore, choosing a low value for α can reduce the likelihood of Type I errors. The result here is that if the null hypothesis is false, it may be more difficult to reject using a lower value for α. The alpha value or statistical significance threshold is arbitrary. Which value to use depends on your field of study.

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4 0
1 year ago
A ball is attached to a string of length 3 m to make a pendulum. The pendulum is placed at a location that is away from the Eart
Musya8 [376]

1) 0.61 m/s^2

2) 13.9 s

Explanation:

1)

The acceleration due to gravity is the acceleration that an object in free fall (acted upon the force of gravity only) would have.

It can be calculated using the equation:

g=\frac{GM}{r^2} (1)

where

G is the gravitational constant

M=5.98\cdot 10^{24} kg is the Earth's mass

r is the distance of the object from the Earth's center

The pendulum in the problem is at an altitude of 3 times the radius of the Earth (R), so its distance from the Earth's center is

r=4R

where

R=6.37\cdot 10^6 m is the Earth's radius

Therefore, we can calculate the acceleration due to gravity at that height using eq.(1):

g=\frac{GM}{(4R)^2}=\frac{(6.67\cdot 10^{-11})(5.98\cdot 10^{24})0.}{(4\cdot 6.37\cdot 10^6)^2}=0.61 m/s^2

2)

The period of a simple pendulum is the time the pendulum takes to complete one oscillation. It is given by the formula

T=2\pi \sqrt{\frac{L}{g}}

where

L is the length of the pendulum

g is the acceleration due to gravity at the location of the pendulum

Note that the period of a pendulum does not depend on its mass.

For the pendulum in this problem, we have:

L = 3 m is its length

g=0.61 m/s^2 is the acceleration due to gravity (calculated in part 1)

Therefore, the period of the pendulum is:

T=2\pi \sqrt{\frac{3}{0.61}}=13.9 s

4 0
3 years ago
What is magnification
il63 [147K]
The action or process of magnifying something or being magnified, especially visually. Hope this helped
5 0
4 years ago
An external force of 5N is applied to a go-kart that is opposite it’s direction of travel for 5 seconds. What is the resulting m
Greeley [361]

Answer:

25N.s=25kgm/s

Explanation:

The resulting momentum in this case is equal to the impulse created by the force 5N during 5 seconds

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5 0
3 years ago
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