Describiry Clectrical Porte

Physics

2 answers:

sineoko [7]4 years ago

7 0

Answer:

Explanation:

zalisa [80]4 years ago

5 0

Answer:

decreases

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The impulse given to a ball with mass of 2 kg is 16 N*s. If the ball starts from rest, what is its final velocity?

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The impulse is equal to the variation of momentum of the object:
$I=\Delta p = m \Delta v$
where m is the mass object and $\Delta v = v_f - v_i$ is the variation of velocity of the object.

The ball starts from rest so its initial velocity is zero: $v_i=0$ . So we can rewrite the formula as
$I=m v_f$
or
$v_f = \frac{I}{m}$

and since we know the impulse given to the ball (I=16 Ns) and its mass (m=2 kg), we can find the final velocity of the ball:
$v_f = \frac{16 Ns}{2 kg}= 8 m/s$

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