Scientist Jordan makes a discovery and publishes the results for other scientists to read. Scientist Leesha tries to repeat the
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<h2> v= 21.47m/s </h2>Explanation:
For the car to turn at the about the centripetal force must not be greater than the static friction between the tires and the road
we will use the expression relating centripetal force and static friction below
let U represent the coefficient of static friction
Given that
U= 0.50
mass m= 1200-kg
radius r= 94.0 m
Assuming g= 9.81 m/s^2
substituting our given data in to expression we can solve for the speed V
making v the subject of formula we have
v= 21.47m/s
<em><u>hence the maximum velocity of the car is 21.47m/s</u></em>
The average acceleration of the cheetah is 7.75 m/s²
The given parameters;
velocity of the cheetah, v = 31 m/s
time of motion, t = 4 seconds
The average acceleration of the cheetah is calculated as follows;
where;
v is the final velocity
u is the initial velocity
t is the time of motion
Assuming the cheetah started from rest, the initial velocity, u = 0
The average acceleration is calculated as follows;
Thus, the average acceleration of the cheetah is 7.75 m/s²
Learn more here: brainly.com/question/17280180