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4 years ago

Calculate the mass of an object with a density of 102.5 g/mL and volume of 375 mL.

Physics

1 answer:

AveGali [126]4 years ago

6 0

Answer:

38,437.5

Explanation:

Density(d)= 102.5g/ml

Volume (v)=375ml

Mass(m) = ?

D =m/v

102.5= m/375

102.5*375=m

38,437.5=m

therefore Mass = 38,437.5g/ml.

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A red laser from the physics lab is marked as producing 632.8-nm light. When light from this laser falls on two closely spaced s

BARSIC [14]

Answer:

The wavelength is $\lambda_R = 649 *10^{-9}\ m$

Explanation:

From the question we are told that

The wavelength of the red laser is $\lambda_r = 632.8 \ nm = 632.8 *10^{-9}\ m$

The spacing between the fringe is $y_r = 6.00\ mm = 6.00*10^{-3} \ m$

The spacing between the fringe for smaller laser point is $y_R = 6.19 \ mm = 6.19 *10^{-3} \ m$

Generally the spacing between the fringe is mathematically represented as

$y = \frac{D * \lambda }{d}$

Here $D$ is the distance to the screen

and d is the distance of the slit separation

Now for both laser red light light and small laser point D and d are same for this experiment

$\frac{y_r}{\lambda_r} = \frac{D}{d}$

=> $\frac{y_r}{\lambda_r} = \frac{y_R}{\lambda_R}$

Where $\lambda_R$ is the wavelength produced by the small laser pointer

$\frac{6.0 *10^{-3}}{ 632.8*10^{-9}} = \frac{ 6.15 *10^{-9}}{\lambda_R}$

=> $\lambda_R = 649 *10^{-9}\ m$

7 0

3 years ago

A cleaver physics professor wants to create a situation where a block starts from rest at the top of a 31.0° inclined plane and

UNO [17]

Answer:

Explanation:

Let the length of inclined plane be L .

work done by gravity on the block

= force x length of path

= mg sinθ x L , m is mass of the block , θ is inclination of path

This in converted into potential energy of compressed spring

1/2 k x² = mgL sin31 , k is force constant . x is compression

.5 x 3400 x .37² = 33 x9.8 x sin31 L

L = 1.4

Length of incline = 1.4 m .

8 0

4 years ago

A 1-ton shark swims to the right toward a beach. In which direction is the reaction force to the shark's weight?

Natasha_Volkova [10]

The Answer you are looking for is D.

7 0

3 years ago

object carries a charge of -8.1 ÂµC, while another carries a charge of -2.0 ÂµC. How many electrons must be transferred from the

LenKa [72]

Number of electrons transferred: $1.91\cdot 10^{13}$

Explanation:

The charge on the first object is

$Q_1 = -8.1\mu C$

while the charge on the 2nd object is

$Q_2=-2.0 \mu C$

When they are in contact, the final charge on each object will be

$Q=\frac{Q_1+Q_2}{2}=\frac{-8.1+(-2.0)}{2}=-5.05 \mu C$

So, the amount of charge (electrons) transferred from the 1st object to the 2nd object is

$\Delta Q = Q_1 - Q = -8.1 -(5.05)=-3.05 \mu C = -3.05\cdot 10^{-6}C$

The charge of one electron is

$e=-1.6\cdot 10^{-19}C$

Therefore, the number of electrons transferred is

$N=\frac{Q}{e}=\frac{-3.05\cdot 10^{-6}}{-1.6\cdot 10^{-19}}=1.91\cdot 10^{13}$

Learn more about electrons:

brainly.com/question/2757829

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3 years ago

A circular solenoid of radius R = 2cm passes through a square loop of wire with 1 turn and sides of length ℓ = 5cm. The solenoid

ankoles [38]

The answer for this problem is D

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4 years ago