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3 years ago

Pyruvic acid can be regarded as the end product of _________________.

Chemistry

1 answer:

Alex_Xolod [135]3 years ago

3 0

Pyruvic acid is the end product of the Link reaction in respiration.

Hope that helps

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Sixty-five percent of the mass of bone is a compound called hydroxyapatite. sixty-five percent of the mass of bone is a compound

mafiozo [28]

True. Its simple how i remeberd was the bone has 650,000 cells and the bone has 65% hydroxyapatite

5 0

2 years ago

PLEASE HELP!! GIVING BRAINLIEST

RSB [31]

Answer:

The answer is "0.00172172603".

Explanation:

Given:

$Mass (M) = 1.60 \times 10^{-3} \ g\\\\Density (D) = 9.293 \times 10^{-1} \ \frac{g}{cm^3}\\\\Volume (V) = ?$

Formula:

$\to \bold{V = \frac{M}{D}}$

$= \frac{1.60 \times 10^{-3}}{9.293 \times 10^{-1}} \\\\ = \frac{1.60 \times 10^{1}}{9.293 \times 10^{3}} \\\\ = \frac{1.60 \times 10}{9.293 \times 1000} \\\\ = \frac{1.60 }{9.293 \times 100} \\\\ = \frac{1.60 }{929.3 } \\\\= 0.00172172603$

4 0

2 years ago

1.For the reaction P4 O10(s) + 6H2O(l) → 4H3PO4(aq), what mass of P

Alex17521 [72]

P₄O₁₀ + 6H₂O → 4H₃PO₄
The equation shows us that the molar ratio of
P₄O₁₀ : 6H₂O = 1:6

We also know that one mole of a substance contains 6.02 x 10²³ particles. We can use this to calculate the moles of water.
moles(H₂O) = (5.51 x 10²³) / (6.02 x 10²³)
= 0.92 mole
That means moles of P₄O₁₀ = 0.92 / 6
= 0.15

Each mole of P₄O₁₀ contains 4 moles of P.
moles(P) = 4 x 0.15 = 0.6 mol
Mr of P = 207 grams per mol
Mass of P = 207 x 0.6
= 124.2 grams

5 0

2 years ago

Read 2 more answers

If this decay has a half life of 2.60 years, what mass of 72.5 g of sodium 22 will remain after 15.6 years

Vlad1618 [11]

Sodium-22 remain : 1.13 g

<h3>Further explanation </h3>

The atomic nucleus can experience decay into 2 particles or more due to the instability of its atomic nucleus.

Usually, radioactive elements have an unstable atomic nucleus.

General formulas used in decay:

$\large{\boxed{\bold{N_t=N_0(\dfrac{1}{2})^{T/t\frac{1}{2} }}}$

T = duration of decay

t 1/2 = half-life

N₀ = the number of initial radioactive atoms

Nt = the number of radioactive atoms left after decaying during T time

half-life = t 1/2=2.6 years

T=15.6 years

No=72.5 g

$\tt Nt=72.5.\dfrac{1}{2}^{15.6/2.6}\\\\Nt=72.5.\dfrac{1}{2}^6\\\\Nt=1.13~g$

8 0

3 years ago

What is the mass of an osmium block that measures 6.70 cm × 9.20 cm × 3.30 cm? The density of osmium is given as 22.610 g/cm3. N

alexira [117]

Answer:

m= 4,599.145 g

Explanation:

Let m = mass, d = density and V = volume of the osmium block.

m = d x V

m = 22.610 g/cm3 x (6.70 x 9.20 x 3.3) cm3

m = 4,599.145 g

7 0

2 years ago