¡Hellow!
For this problem, first, lets convert the seconds in hours:
5,4x10³
5400
h = sec / 3600
h = 5400 s / 3600
h = 1,5
Let's recabe information:
d (Distance) = 386 km
t (Time) = 1,5 h
v (Velocity) = ?
For calculate velocity, let's applicate formula:
![\boxed{\boxed{\textbf{d = v * t} } }](https://tex.z-dn.net/?f=%5Cboxed%7B%5Cboxed%7B%5Ctextbf%7Bd%20%3D%20v%20%2A%20t%7D%20%7D%20%7D)
Reeplace according we information:
386 km = v * 1,5 h
v = 386 km / 1,5 h
v = 257,33 km/h
The velocity of the train is of <u>257,33 kilometers for hour.</u>
<u></u>
Extra:
For convert km/h to m/s, we divide the velocity of km/h for 3,6:
m/s = km/h / 3,6
Let's reeplace:
m/s = 257,33 km/h / 3,6
m/s = 71,48
¿Good Luck?
Answer:
doubles
Explanation:
The relationship between angular speed and linear speed in case of a circular motion is the following:
![v=\omega r](https://tex.z-dn.net/?f=v%3D%5Comega%20r)
where
v is the linear speed
is the angular speed
r is the distance from the centre of the circular path
In this proble, the pet hamster moves to a point twice as far from the center; this means that its distance from the centre, r', is doubled:
![r'=2r](https://tex.z-dn.net/?f=r%27%3D2r)
While the angular speed
remains the same. Therefore, the new linear speed is
![v'=\omega r' = \omega (2r)=2 \omega r=2v](https://tex.z-dn.net/?f=v%27%3D%5Comega%20r%27%20%3D%20%5Comega%20%282r%29%3D2%20%5Comega%20r%3D2v)
So, the correct answer is
the linear speed doubles
Answer:
![2.1\times 10^{-9} T](https://tex.z-dn.net/?f=2.1%5Ctimes%2010%5E%7B-9%7D%20T)
Explanation:
We are given that
Frequency,f=800KHz=![800\times 10^{3} Hz](https://tex.z-dn.net/?f=800%5Ctimes%2010%5E%7B3%7D%20Hz)
![1kHz=10^{3} Hz](https://tex.z-dn.net/?f=1kHz%3D10%5E%7B3%7D%20Hz)
Distance,d=4.5 km=![4.5\times 10^{3} m](https://tex.z-dn.net/?f=4.5%5Ctimes%2010%5E%7B3%7D%20m)
1 km=1000 m
Electric field,E=0.63V/m
We have to find the magnetic field amplitude of the signal at that point.
![c=3\times 10^8 m/s](https://tex.z-dn.net/?f=c%3D3%5Ctimes%2010%5E8%20m%2Fs)
We know that
![B=\frac{E}{c}](https://tex.z-dn.net/?f=B%3D%5Cfrac%7BE%7D%7Bc%7D)
![B=\frac{0.63}{3\times 10^8}=0.21\times 10^{-8} T](https://tex.z-dn.net/?f=B%3D%5Cfrac%7B0.63%7D%7B3%5Ctimes%2010%5E8%7D%3D0.21%5Ctimes%2010%5E%7B-8%7D%20T)
![B=2.1\times 10^{-9} T](https://tex.z-dn.net/?f=B%3D2.1%5Ctimes%2010%5E%7B-9%7D%20T)
Rotational kinetic energy <span>is the kinetic energy of an object, proportional to the object's moment of inertia and the square of its angular velocity.</span>