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suter [353]
2 years ago
10

What is the net force needed to lift a full grocery sack (weighing 210N) uniformly?

Physics
1 answer:
marta [7]2 years ago
5 0
Its a Net force of 21.41404
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Your car's speedometer works in much the same way as its odometer, except that it converts the angular speed of the wheels to a
brilliants [131]

Answer:

Speed will be 30810 rpm      

Explanation:

We have given diameter of the tire d = 24 inch

So radius r=\frac{d}{2}=\frac{24}{2}=12imch

We have given linear velocity v = 35 mph

We know that linear velocity is given by v=\omega r

35=\omega \times 12

\omega =\frac{35}{12}\times \frac{63360}{60}=3080rad/min

As we know that 1 mile = 63360 inch and 1 hour = 60 min

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3 years ago
An electromagnetic wave is produced by:
Ray Of Light [21]
A. an accelerating charged charged particle or changing magnetic fields
4 0
2 years ago
How are mountain ecosystems different from other ecosystems?
Andreyy89

Answer:

They host three or more distinct ecosystems at different elevations.

Explanation:

I checked it, and its right.

3 0
2 years ago
Allison is looking through a telescope at an object in space. The object looks like a very small planet, and it does not have a
Verizon [17]

Answer:

Allison is probably looking at the asteroid.

Explanation:

  • Asteroids are the giant gas balls of inner solar system that are present in the space.
  • Asteroids orbits around the sun in very irregular ans strange path unlike the other planets.
  • This is also the reason why it's called as the minor planets.
  • It could have been comet but if it had been a comets he must have seen the tail but asteroids do not have any tail like structure.
8 0
3 years ago
Damping is negligible for a 0.135-kg object hanging from a light, 6.30-N/m spring. A sinusoidal force with an amplitude of 1.70
IceJOKER [234]

Answer:

0.72 Hz minimum frequency

Explanation:

When the damping is negligible,Amplitude is given as

A = (F/m)/[\sqrt{(\omega ^{^{2}}-\omega _{o}^{2}})^2

here \omega _{o}^{2}= k/m = (6.30)/(0.135) = 46.67 N/m kg

F / mA = 1.70/(0.135)(0.480) = 26.2 N/m kg

From the above equation , rearranging for ω,

\omega ^{2}= \omega _{o}^{2}\pm F/m

⇒ ω² =46.67 ± 26.2 = 72.87 or 20.47

⇒ ω = 8.53 or 4.52 rad/s

Frequency = f

ω=2 π f

⇒ f = ω / 2π =  8.53 /6.28  or 4.52 / 6.28 = 1.36 Hz or 0.72 Hz

The lower frequency is 0.72 Hz and higher is 1.36 Hz

8 0
3 years ago
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