3 years ago

What is the net force needed to lift a full grocery sack (weighing 210N) uniformly?

1 answer:

marta [7]3 years ago

5 0

Its a Net force of 21.41404

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Andreyy89

Answer:

A) $T=209.94N$

B) $F=75.24N$

Explanation:

Using the free body diagram and according to Newton's first law, we have:

$\sum F_y=Tcos(21^\circ)-mg=0(1)\\\sum F_x=F-Tsin(21^\circ)=0(2)$

A) Solving (1) for T:

$T=\frac{mg}{cos(21^\circ)}\\T=\frac{20kg(9.8\frac{m}{s^2})}{cos(21^\circ)}\\T=209.94N$

B) Solving (2) for F:

$F=Tsin(21^\circ)\\F=(209.94N)sin(21^\circ)\\F=75.24N$

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