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suter [353]
3 years ago
10

What is the net force needed to lift a full grocery sack (weighing 210N) uniformly?

Physics
1 answer:
marta [7]3 years ago
5 0
Its a Net force of 21.41404
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A 1200 kg car accelerates from rest for 45 meters in 6.0 seconds. What is the net force on the car?​
Alja [10]

Answer:

Explanation:

At first, you have to get the acceleration value from the given data.

s=ut+\frac{1}{2}at^{2}

s= 45m

u= 0 m/s

t = 6s

a = ?

45 = 0+ 0.5 × a × 6²

45 = 0.5 × 36 × a

45 = 18a

a = 2.5 m/s²

Now, you can use F=ma equation

F = ?

m = 1200kg

a = 2.5 m/s²

F = 1200 × 2.5

F = 3000 N

8 0
4 years ago
A gas can compress and change shape easily. How do these properties relate to the motion of atoms in a gas?
Ksju [112]

Answer:

The atoms in a gas move about freely and have a lot of space between them.

Explanation:

Just took the test on edge 2020

3 0
3 years ago
Your spaceship lands on an unknown planet. To determine the characteristics of this planet, you drop a wrench from 4.50 m above
Virty [35]

8.98×10^6\:\text{m}

Explanation:

First we need to find the acceleration due to gravity on the planet. The wrench took 0.809 s to fall from a height of 4.50 m so we can use the equation

y = -\frac{1}{2}gt^2

Solving for g, we get

g = -\dfrac{2y}{t^2} = -\dfrac{2(-4.50\:\text{m})}{(0.809\:\text{s})} = 13.8\:\text{m/s}^2

Recall that the acceleration due to gravity on a planet's surface can be written as

g = G\dfrac{M_p}{R_p^2}

We can express the mass of the planet M_p in terms of its density \rho as follows:

M_p = \rho \left(\dfrac{4\pi}{3}R_p^3\right) = \dfrac{4\pi}{3}\rho R_p^3

The expression for g then becomes

g = \dfrac{G}{R_p^2} \left(\dfrac{4\pi}{3}\rho R_p^3\right) = \dfrac{4\pi G}{3}\rho R_p

Solving for R_p, we get

R_p = \dfrac{3g}{4\pi G\rho}

\:\:\:\:\:\:\:= \left[\dfrac{3(13.8\:\text{m/s}^2)}{4\pi (6.674×10^{-11}\:\text{Nm}^2\text{/kg}^2)(5500\:\text{kg/m}^3)}\right]

\:\:\:\:\:\:\:= 8.98×10^6\:\text{m}

3 0
3 years ago
What will happen if the value of g that is 9.8m/s^2 becomes zero???
quester [9]

Answer:

everything will fly about endlessly

Explanation:

the gravitational mass or whatever is now zero, this implies that object that are attracted to each other would no longer gain that attraction due to the absence of the force of attraction putting everything in place

8 0
3 years ago
Read 2 more answers
a bubble of air of volume 1cm^3 is released by a deep sea diver at a depth where the pressure is 4.0 atmospheres. assuming its t
lys-0071 [83]

Answer:

hope this helps!

Explanation:

Volume of the air bubble, V1=1.0cm3=1.0×10−6m3

Bubble rises to height, d=40m

Temperature at a depth of 40 m, T1=12oC=285K

Temperature at the surface of the lake, T2=35oC=308K

The pressure on the surface of the lake: P2=1atm=1×1.103×105Pa 

The pressure at the depth of 40 m: P1=1atm+dρg

Where,

ρ is the density of water =103kg/m3

g is the acceleration due to gravity =9.8m/s2

∴P1=1.103×105+40×103×9.8=493300Pa

We have T1P1V1=T2P2V2

Where, V2 is the volume of the air bubble when it reaches the surface.

V2=

8 0
3 years ago
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