All of the elements on periodic table are found in nature true or false
1 answer:
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Answer:
See explanation below
Explanation:
The question is incomplete. However in picture 1, you have the starting materials and the structure of the product, which you miss in this part.
Now, in picture 2, you have the starting reactant and the product, and the mechanism that is taking place here.
First, all what we have here is an acid base reaction. In the first step, we are using the acid medium to convert the reactant into an alcohol. The bromine there, is not leaving the molecule yet, because it's neccesary for the next step. The starting reactant is an alkene, in that way, we can convert the reactant in the first step into a secondary alcohol. In other words, the first reaction is a alkene hydration.
In the second step, we use a strong base. You may say this is a strong nucleophile and will do a Sn2 reaction to form another alcohol there, but it's not the case, because, before any kind of reaction happens, the priority here is always the acid base, so the base will react with the acidic hydrogen. In this case, it will substract an hydrogen from the OH. When this happens, the lone pair will do an auto condensation here, and attacks the bromine in the molecule. In this way, the molecule will become a cyclomolecule, and that way it form the final product.
See picture 2, for mechanism
<u>Answer:</u> The percentage yield of HF is 73.36 %
<u>Explanation:</u>
To calculate the number of moles, we use the equation:
....(1)
For calcium fluoride:
Given mass of calcium fluoride = 6.25 kg = 6250 g (Conversion factor: 1 kg = 1000 g)
Molar mass of calcium fluoride = 78.07 g/mol
Putting values in above equation, we get:
For the given chemical reaction:
By Stoichiometry of the reaction:
1 mole of calcium fluoride produces 2 moles of hydrofluoric acid
So, 80.05 moles of calcium fluoride will produce = of hydrofluoric acid
Now, calculating the theoretical yield of hydrofluoric acid using equation 1, we get:
Moles of of hydrofluoric acid = 160.1 moles
Molar mass of hydrofluoric acid = 20.01 g/mol
Putting values in equation 1, we get:
To calculate the percentage yield of hydrofluoric acid, we use the equation:
Experimental yield of hydrofluoric acid = 2.35 kg
Theoretical yield of hydrofluoric acid = 3.20 kg
Putting values in above equation, we get:
Hence, the percentage yield of HF is 73.36 %