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Kamila [148]
3 years ago
11

Which of these substances most likely dissolve in water? check all that apply.

Chemistry
1 answer:
vlada-n [284]3 years ago
8 0

The answer is:

glucose, a polar organic compound

silver nitrate, an ionic compound

<span>The two have net charges that enable them to attract with water molecules. Water molecules are partly charged because of the arrangement of electron clouds around the molecule. The oxygen atom in the molecule is more electronegative than the two hydrogens. Therefore water is able to form electrostatic attraction forces with the charged molecules</span>




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Which is untrue about covalent compounds?
scoundrel [369]

The untrue statement is that they high melting points.  

The covalent compounds are the compounds exhibiting strong intra-molecular bonds. This is due to the tightness of the atoms within the covalent molecules. The force of attraction between the individual molecules in a covalent compound seems to be weak. The covalent compounds exhibit weak intermolecular forces that hold the atoms together due to this they have a low melting point.  


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A patient needs to take 625 mg of ibuprofen twice daily. The pills in the bottle are each 250. mg. How many pills does the patie
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2 and a half
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2 and a half
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3 years ago
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An isotope of potassium with a half-life of roughly one billion years is often used in radioactive dating. This isotope decays t
melisa1 [442]

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Explanation :

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_Z^A\textrm{X}+_{-1}^0\textrm{e}\rightarrow _{Z-1}^A\textrm{Y}

The equation for the given reaction is,

_{19}^{40}\textrm{K}+_{-1}^0\textrm{e}\rightarrow _{18}^{40}\textrm{Ar}

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7 0
3 years ago
if the percent by volume is 2% and the volume of solution is 250 mL what is the volume of solute and solution
Liula [17]

Answer:

Solute = 5 mL; solution = 250 mL  

Explanation:

The formula for percent by volume is

\text{Percent by volume} = \dfrac{\text{Volume of solute}}{\text{Volume of solution}}\times 100 \, \%

If you have 250 mL of a solution that is 2 % v/v,

\begin{array}{rcl}2 \, \% & = & \dfrac{\text{Volume of solute}}{\text{250 mL}}\times 100 \, \%\\\\2 \times \text{ 250 mL} & = & \text{Volume of solute} \times 100\\\text{Volume of solute} & = & \dfrac{2 \times 250\text{ mL}}{100}\\\\ & = & \textbf{5 mL}\\\end{array}

If there is no change of volume on mixing,

Volume of solution = 250 mL

 -Volume of solute = <u>     </u><u>5</u><u>      </u>

 Volume of solvent = 245 mL

5 0
3 years ago
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