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Answer:
R₁ = 14.44 R₂
Explanation:
For sun-earth system
GMm/R² = mω²R
GM =ω²R³
GM₁ =ω₁²R₁³
For star - planet system
GM₂ =ω₂²R₂³
Dividing
M₁ / M₂ = ω₁²R₁³ / ω₂²R₂³
R₁³ /R₂³ = M₁ω₂² / ω₁²M₂
= M₁T₁²/T₂²M₂
Given
M₁ / M₂ = 1 / 0.7
T₁ = 365 days
T₂ = 9.5 days
R₁³ /R₂³ = M₁²365² /9.5² (.7M₁ )²
(R₁ /R₂)³ =365² / 9.5² X .7²
= 3012
R₁ /R₂
= 14.44
R₁ = 14.44 R₂
The length of the spring 2 due to arrangement of the equal masses is determined as 0.238 m.
<h3>Extension of the spring 2</h3>
The extension of the spring 2 is determined from the net force acting on spring 2.
F(net) = Kx
<em>Net force on spring 2 = sum of forces acting downwards - sum of forces acting upwards.</em>
Net force on spring 2 = (force on 2 + force on 3) - (force on 1)
F(net) = (m₂ + m₃)g - (m₁)g
F(net) = (6.67 + 6.67)9.8 - (6.67)9.8
F(net) = 130.732 - 65.366
F(net) = 65.366 N
x = F/k
x = (65.366)/(8130)
x = 0.00804 m
The length of spring 2 = x + 0.23 m
= 0.00804 m + 0.23 m = 0.238 m
Thus, the length of the spring 2 due to arrangement of the equal masses is determined as 0.238 m.
Learn more about extension of elastic material here: brainly.com/question/26838571
Answer:
YOP
Explanation:
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