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vesna_86 [32]
3 years ago
9

A 70 kilogram mountaineer is standing on the summit of Mt. Everest. The distance between the mountaineer and the center of Earth

is 6.39 × 106 meters. What is the magnitude of the force of gravity acting on the mountaineer? (The value of G is 6.673 × 10-11 newton meter2/kilogram2. The mass of Earth is 5.98 × 1024 kilograms.)
90.50 newtons



111.5 newtons



684.1 newtons



4041.7 newtons
Physics
2 answers:
Ilia_Sergeevich [38]3 years ago
8 0
 <span>F = GMm/r² 

F = (6.673*10^-11)(5.98*10^24)(70)/(6.39*10^... 

F = 684 N (3sf)</span>
madreJ [45]3 years ago
5 0
The force due to gravity between two point masses is given by:
F = GMm/r²; where G is the gravitational constant, M is the larger mass, m is the smaller mass, and r is the distance between the two.
F =  (6.673 × 10⁻¹¹ × 5.98 × 10²⁴ × 70) / (6.39 × 10⁶)²
F = 684.1 N
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Explanation:

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we can now use the formula v^2 = u^2 + 2as where v = final velocity, u = initial velocity, a = acceleration and s = distance

rearranging v^2 = u^2 + 2as the distance is

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