Answer:
1.6605 × 10⁻²³ g / atom , 9.99 amu
Explanation:
Atoms present in 1 mole = 6.022 × 10²³ atoms
Given that
Moles of common Eastern mole = 8.3 moles
So,
Atoms in 8.3 moles are:
8.3 moles = 6.022 × 10²³ × 8.3 atoms
Also,
Average mass = Mass of the sample / Number of atoms
Mass of sample = 83 g
Average mass = 83 g / 6.022 × 10²³ × 8.3 atoms = 1.6605 × 10⁻²³ g / atom
In amu :
1 amu = 1.66 × 10⁻²⁴ g / atom
So,
Average mass = 1.6605 × 10⁻²³ / 1.66 × 10⁻²⁴ amu = 9.99 amu
It's depending on what size of the tree it is. For example, if the tree is large it will block most of the water that runs through. If the tree is small it shouldn't do as much besides block a little amount of water and it will probably go down stream.
This is based on my thinking
The oxidation number of an element is the number of electrons that are gained or lost by the element to form a chemical bond.
the net oxidation number of the ion is its charge.
compound (NH₄)₂Cr₂O₇ is made of cation - NH₄⁺ and anion - Cr₂O₇²⁻
oxidation number of ion - -2
(oxidation number of Cr x 2 Cr atoms) +(oxidation number of O x 7 O atoms )= -2
oxidation number of Cr = y
oxidation number of O = -2
(y x 2) + (-2 x 7) = -2
2y - 14 = -2
2y = 12
y = + 6
therefore oxidation number of Cr is +6
The molecular geometry is trigonal planar. I would choose E