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stepladder [879]
3 years ago
12

You are on a cruise ship traveling north at a speed of 13 m/s with respect to land. 1) if you walk north toward the front of the

ship, with a speed of 2.8 with respect to the ship, what is your velocity with respect to the land
Physics
1 answer:
Brrunno [24]3 years ago
5 0

In order to find the our own velocity with respect to land,we need to apply the theory of relative velocity.


Now consider the velocity of the ship traveling towards the north with respect to land as A.Consider our own velocity headed northwards as B.

The relative velocity is the velocity that the body A would appear to an observer on the body B and vice versa.


In this case the relative velocity would be arrived by summing up our velocity with the velocity of the ship as the object (I) is travelling in the ship.


Relative velocity = Velocity of Body A+ Velocity of Body B.


Velocity of the ship traveling towards the north with respect to land(A)= 13.0m/s. (Given)

Our own velocity headed northwards(B)= 2.8 m/s.



Relative velocity = Velocity of Body A+ Velocity of Body B.


Relative velocity= 13.0 + 2.8 = 15.8m/s.


Thus our own velocity with respect to the land is 15.8 m/s.



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<em>ANSWER: 3.90 m/s</em>
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Wendy drives a minibus at a constant speed of 47 Kph. How far can Wendy travel in 3 hours?
garik1379 [7]

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Which of the following is an example of a force?
strojnjashka [21]

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6 0
3 years ago
A block of 250-mm length and 48 × 40-mm cross section is to support a centric compressive load P. The material to be used is a b
Marrrta [24]

Answer:

153.6 kN

Explanation:

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k = 95*10^9 * 0.048*0.04/0.25 = 729.6 MN/m

0.12% of the original length is:

0.0012 * 0.25 m = 0.0003  m

Hooke's law:

F = x * k

Where x is the change in length

F = 0.0003 * 729.6*10^6 = 218.88 kN (maximum force admissible by deformation)

The compressive load will generate a stress of

σ = F / A

F = σ * A

F = 80*10^6 * 0.048 * 0.04 = 153.6 kN

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8 0
3 years ago
PE=30J, m=?, g=10m/s2, h=10m
OleMash [197]
Based on the given, this is probably a gravitational potential energy problem (PEgrav). The formula for PEgrav is:

PEgrav = mgh

Where:
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g = acceleration due to gravity
h = height (m)

With this formula you can derive the formula for your unknown, which is mass. First put in what you know and then solve for what you do not know.

PEgrav=mgh
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Do operations that you can with what is given first.

30J=m(100m)

Transpose the 100 to the other side of the equation. Do not forget that when you transpose, you do the opposite operation.

\frac{30}{100} =m

m = 0.30kg

5 0
3 years ago
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