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Rom4ik [11]
3 years ago
14

How long will it take a cyclist to accelerate to 12 m/s starting from rest if he rides with an average acceleration of 1.2 m/s^2

?
"using acceleration formula"
Physics
1 answer:
igor_vitrenko [27]3 years ago
3 0

Answer:

<em>The cyclist takes 10 seconds to accelerate to 12 m/s.</em>

Explanation:

<u>Constant Acceleration Motion</u>

It's a type of motion in which the velocity of an object changes by an equal amount in every equal period of time.

Being a the constant acceleration, vo the initial speed, vf the final speed, and t the time, the following relation applies:

v_f=v_o+at

Solving for t:

\displaystyle t=\frac{v_f-v_o}{a}

The cyclist starts from rest (vo=0) and moves at vf=12 m/s with an acceleration a=1.2\ m/s^2.

Calculate the time:

\displaystyle t=\frac{12-0}{1.2}

\displaystyle t=\frac{12}{1.2}

\boxed{t=10\ sec}

The cyclist takes 10 seconds to accelerate to 12 m/s.

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Two parallel-plate capacitors have the same plate area. Capacitor 1 has a plate separation twice that of capacitor 2, and the qu
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Answer:

V_1=8 V_2

Explanation:

Given that:

  • Area of the plate of capacitor 1= Area of the plate of capacitor 2=A
  • separation distance of capacitor 2, d_2=d
  • separation distance of capacitor 1, d_1=2d
  • quantity of charge on capacitor 2, Q_2=Q
  • quantity of charge on capacitor 1, Q_1=4Q

We know that the Capacitance of a parallel plate capacitor is directly proportional to the area and inversely proportional to the distance of separation.

Mathematically given as:

C=\frac{k.\epsilon_0.A}{d}.....................................(1)

where:

k = relative permittivity of the dielectric material between the plates= 1 for air

\epsilon_0 = 8.85\times 10^{-12}\,F.m^{-1}

From eq. (1)

For capacitor 2:

C_2=\frac{k.\epsilon_0.A}{d}

For capacitor 1:

C_1=\frac{k.\epsilon_0.A}{2d}

C_1=\frac{1}{2} [ \frac{k.\epsilon_0.A}{d}]

We know, potential differences across a capacitor is given by:

V=\frac{Q}{C}..........................................(2)

where, Q = charge on the capacitor plates.

for capacitor 2:

V_2=\frac{Q}{\frac{k.\epsilon_0.A}{d}}

V_2=\frac{Q.d}{k.\epsilon_0.A}

& for capacitor 1:

V_1=\frac{4Q}{\frac{k.\epsilon_0.A}{2d}}

V_1=\frac{4Q\times 2d}{k.\epsilon_0.A}

V_1=8\times [\frac{Q.d}{k.\epsilon_0.A}]

V_1=8 V_2

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3 years ago
A sinusoidal wave has period 0.20 s and wavelength 2.0 m. What is the wave speed?
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Answer:10m/s

Explanation:

Wave speed ,v=for

Where π= wavelength=2m

Period =1/f f=frequency of wave

F=1/period

=1/0.2=5Hz

So speed of waves,v=5×2=10m/s

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3 years ago
The planet Saturn has a mass that is 95 times Earth's mass and a radius that is 9.4 times Earth's radius. What is the accelerati
ziro4ka [17]

Answer:

10.55111 m/s²

Explanation:

M = Mass of Saturn = 95\times 5.972\times 10^{24}\ kg

r = Radius of Saturn = 9.4\times 6.371\times 10^6\ m

G = Gravitational constant = 6.67 × 10⁻¹¹ m³/kgs²

Acceleration due to gravity is given by

g=\dfrac{GM}{r^2}\\\Rightarrow g=\dfrac{6.67\times 10^{-11}\times 95\times 5.972\times 10^{24}}{(9.4\times 6.371\times 10^6)^2}\\\Rightarrow g=10.55111\ m/s^2

The acceleration due to gravity on Saturn is 10.55111 m/s²

4 0
3 years ago
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