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Assoli18 [71]
4 years ago
8

Nicolaus Copernicus believed that the: sun revolved around the earth sun was the center of the solar system movement of planets

could explain weather stars and planets represented spirits
Physics
1 answer:
Vitek1552 [10]4 years ago
7 0
Nicolaus Copernicus spearheaded the idea of heliocentrism, that is, that the sun was the center of the solar system. Back in his time, a lot of astronomers and scientists believed that the earth was the center of the solar system. This so called belief was called geocentrism. Nicolaus was one fo the first few who pushed heliocentrism.
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When the magnetic flux through a single loop of wire increases by , an average current of 40 A is induced in the wire. Assuming
Zielflug [23.3K]

COMPLETE QUESTION:

<em>When the magnetic flux through a single loop of wire increases by </em>30 Tm^2<em> , an average current of 40 A is induced in the wire. Assuming that the wire has a resistance of </em><em>2.5 ohms </em><em>, (a) over what period of time did the flux increase? (b) If the current had been only 20 A, how long would the flux increase have taken?</em>

Answer:

(a). The time period is 0.3s.

(b). The time period is 0.6s.

Explanation:

Faraday's law says that for one loop of wire the emf \varepsilon is

(1). \: \: \varepsilon = \dfrac{\Delta \Phi_B}{\Delta t }

and since from Ohm's law

\varepsilon  = IR,

then equation (1) becomes

(2). \: \:IR= \dfrac{\Delta \Phi_B}{\Delta t }.

(a).

We are told that the change in magnetic flux is \Phi_B = 30Tm^2,  the current induced is I = 40A, and the resistance of the wire is R = 2.5\Omega; therefore, equation (2) gives

(40A)(2.5\Omega)= \dfrac{30Tm^2}{\Delta t },

which we solve for \Delta t to get:

\Delta t = \dfrac{30Tm^2}{(40A)(2.5\Omega)},

\boxed{\Delta t = 0.3s},

which is the period of time over which the magnetic flux increased.

(b).

Now, if the current had been I =20A, then equation (2) would give

(20A)(2.5\Omega)= \dfrac{30Tm^2}{\Delta t },

\Delta t = \dfrac{30Tm^2}{(20A)(2.5\Omega)},

\boxed{\Delta t = 0.6 s\\}

which is a longer time interval than what we got in part a, which is understandable because in part a the rate of change of flux \dfrac{\Delta \Phi_B}{\Delta t} is greater than in part b, and therefore , the current in (a) is greater than in (b).

7 0
3 years ago
A ramp is needed to allow vehicles to climb a 2 foot wall. The angle of elevation in order for the vehicles to safely go up must
stepan [7]

Answer:

Yes the ramp can be safely used

Explanation:

Here, we have

Length of longest ramp = 5 ft

Height of wall = 2 ft

Therefore, the sine of the angle adjacent to the ramp which is equal to the angle of elevation is given by;

Sin\theta = \frac{Opposite \, side \, to\,  angle}{Hypothenus\, side \, of\,  triangle}

Where:

The opposite side to angle = 2 ft wall and

Hypotenuse side = Ramp = 5 ft

Therefore,

Sin\theta = \frac{2}{5} = 0.4 and θ = sin⁻¹0.4 = 23.55 °

The ramp can be safely used as the angle it is adjacent to is less than the specified 30°.

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