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3 years ago

What is latent heat of fusion?

2 answers:

6 0

There's two forms of latent heat, there's latent heat of fusion which is melting, and there's latent heat of vaporization which is boiling. They describe the direction of energy flow when changing from one thing to the next like solid to liquid, or liquid to gas.

Naddik [55]3 years ago

5 0

If you have a lump of solid at its melting point ... like ice at 32°F ...
you have to put a certain amount of heat into it just to change it
to water at 32°F. That amount of heat, that's used just to change
a solid lump into liquid without changing its temperature, is called
the heat of fusion for that substance.

The number is different for every substance.

For water, it takes 336 joules of heat to melt 1 gram of ice
into 1 gram of water, all at 32°F (0°C).
That's an enormous latent heat of fusion ... more than almost any
other known substance. That's why ice is such a good choice
when you need something to put in your drink to cool it down.
Ice absorbs a huge amount of heat before it melts and the drink
gets watered down.

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A proton travels through a region of uniform magnetic field at an angle \thetaθ relative to the magnetic field. The magnitude of

MArishka [77]

Answer:

$\theta=15.52^{\circ}$

Explanation:

The magnitude of the force of a moving cahrge, in our case a proton, trought a magentic field is given by:

$F=|q||vB|sin(\theta)$ (1)

where:

q is the proton charge ( $q=1.6*10^{-19} C$ )

v is the proton velocity ( $v=5*10^{5} m/s$ )

B is the magnetic field (B = 1.17 T)

Now, we just need to solve the equaton (1) for \theta.

$\theta=sin^{-1}\left(\frac{F}{qvB}\right)$

But the force F = ma, then:

m is the mass of proton ( $m=1.67*10^{-27} kg$ )

a is the acceleration ( $a=1.5*10^{13} m/s^{2}$ )

$\theta=sin^{-1}\left(\frac{m_{p}a}{q_{p}vB}\right)$

$\theta=sin^{-1}\left(\frac{1.67*10^{-27}*1.5*10^{13}}{1.6*10^{-19}*5*10^{5}*1.17}\right)$

$\theta=15.52^{\circ}$

I hope it helps you!

7 0

3 years ago

A wood block is sliding up a wood ramp. if the ramp is very steep, the block will reverse direction at its highest point and sli

DanielleElmas [232]

<span>Answer: So it gets to the top of the ramp and stops. The parallel force pushing it down the ramp is mg sin Î¸, but for it to move, the frictional force must be overcome. This frictional force is ÎĽmg cos Î¸, where ÎĽ is the coefficient of static friction. For movement, then, mg sin Î¸ > ÎĽmg cos Î¸ ==> tan Î¸ > ÎĽ ==> Î¸ > arctan 0.5 = 26.565Â° ==> Î¸ = 27Â°</span>

5 0

3 years ago

Pls help i have test

ludmilkaskok [199]

Answer:

I think the answer is a no. I guess

Explanation:

don't mind if it is write or wrong

5 0

3 years ago

Read 2 more answers

Geosynchronous satellites orbit the Earth at a distance of 42 000 km from the Earth's center. Their angular speed at this height

frozen [14]

Answer:

Force will be 7.97 N

Explanation:

We have given that earth is at s distance of 42000 km from the earth center

So r = 42000 km = 42000000 m

Mass m = 1500 kg

Angular velocity of earth $\omega =7.29\times 10^{-5}rad/sec$

We have to find the force

We know that force is given by

$F=m\omega ^2r=1500\times (7.29\times 10^{-5})^2\times 42000000=797.1615\times 10^{-2}=7.97N$

7 0

3 years ago

What emerging technologies will make hydroelectric energy source safer, more usable, more efficient, cleaner, etc?

vitfil [10]

<h2>Emerging Technologies that will make Hydroelectric Energy Source Safer</h2>

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3 years ago