Answer:
Explanation:
The magnitude of the force of a moving cahrge, in our case a proton, trought a magentic field is given by:
(1)
where:
q is the proton charge (
)
v is the proton velocity (
)
B is the magnetic field (B = 1.17 T)
Now, we just need to solve the equaton (1) for \theta.

But the force F = ma, then:
m is the mass of proton (
)
a is the acceleration (
)

I hope it helps you!
<span>Answer:
So it gets to the top of the ramp and stops. The parallel force pushing it down the ramp is mg sin θ, but for it to move, the frictional force must be overcome. This frictional force is μmg cos θ, where μ is the coefficient of static friction. For movement, then,
mg sin θ > μmg cos θ ==> tan θ > μ ==> θ > arctan 0.5 = 26.565° ==> θ = 27°</span>
Answer:
I think the answer is a no. I guess
Explanation:
don't mind if it is write or wrong
Answer:
Force will be 7.97 N
Explanation:
We have given that earth is at s distance of 42000 km from the earth center
So r = 42000 km = 42000000 m
Mass m = 1500 kg
Angular velocity of earth 
We have to find the force
We know that force is given by

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