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dusya [7]
3 years ago
14

The outer shell electrons in metals are not tightly bound to the nuclei of their atoms they are free to roam throughout the mate

rial moving from atom to atom these materials are good
Physics
1 answer:
Yuliya22 [10]3 years ago
6 0

The pumps which supplies energy to move the water from the ground to a high elevation. The charges that flow throughout the wires.

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posledela
Low levels of fecal coliform
5 0
3 years ago
Read 2 more answers
A bus covers 200m in 5 second.Calculate its speed. ​
QveST [7]
The answer is 40m/s
7 0
3 years ago
Read 2 more answers
If the sprinter accelerates at that rate for a distance of 15 m, and then maintains the velocity he has at that point for the re
ahrayia [7]

Answer:

The time for the entire race is 11.39 sec.

Explanation:

Given that,

Distance = 15 m

Remainder distance = 100 m

Suppose A sprinter begins a race with an acceleration of 3.4 m/s².

We need to calculate the time

Using equation of motion

s=ut+\dfrac{1}{2}at^2

Put the value in the equation

15=0+\dfrac{1}{2}\times3.4\times t^2

t^2=\dfrac{30}{3.4}

t=2.97\ sec

We need to calculate the final velocity of sprinter

Using equation of motion again

v=u+at

Put the value into the formula

v=0+3.4\times2.97

v=10.09\ m/s

We need to calculate the distance covers by sprinter

d=100-15=85\ m

The sprinter need to covers only 85 m.

We need to calculate the time

Using formula of time

t=\dfrac{d}{v}

Put the value into the formula

t'=\dfrac{85}{10.09}

t'=8.42\ sec

We need to calculate the time for the entire race

t''=t+t'

Put the value into the formula

t''=2.97+8.42

t''=11.39\ sec

Hence, The time for the entire race is 11.39 sec.

4 0
3 years ago
A watermelon is dropped from the top of a 80m tall building. We want to find the velocity of the watermelon after it falls for 1
White raven [17]

Answer:

v_f = v_i + at

v_f = 13.23 m/s

Explanation:

Height Of the watermelon when it is dropped is given as

h = 80 m

time of fall under gravity

t = 1.35 s

now if water melon start from rest then we have

v_i = 0

acceleration due to gravity for watermelon

a = 9.81 m/s^2

now we need to find the final speed of watermelon

v_f = v_i + at

so we will have

v_f = 0 + (9.81)(1.35)

v_f = 13.23 m/s

7 0
3 years ago
Imagine that asteroid A that has an escape velocity of 50 m/s. If asteroid B has twice the mass and twice the radius, it would h
padilas [110]

Answer:

The same as the escape velocity of asteorid A (50m/s)

Explanation:

The escape velocity is described as follows:

v=\sqrt{\frac{2GM}{R}}

where G is the universal gravitational constant, M is the mass of the asteroid and R is the radius

and since the scape velocity is 50m/s:

50m/s=\sqrt{\frac{2GM}{R}}

Now, if the astroid B has twice mass and twice the radius, we have that tha mass is: 2M

and the radius is: 2R

inserting these values into the formula for escape velocity:

v=\sqrt{\frac{2G(2M)}{2R} } =\sqrt{\frac{4GM}{2R} } =\sqrt{\frac{2GM}{R} }

and we have found that 50m/s=\sqrt{\frac{2GM}{R}}, so the two asteroids have the same escape velocity.

We found that the expression for escape velocity remains the same as for asteroid A, this because both quantities (radius and mass) doubled, so it does not affect the equation.

The answer is

Asteroid B would have an escape velocity the same as the escape velocity of asteroid A

7 0
3 years ago
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