Answer:
(a) Homogeneous. 4.7 g of MgCl₂.
(b) 9.1 g
Explanation:
(a)
At 200°C, we can dissolve 54.6g of MgCl₂ in 100 g of water. The mass that we could dissolve in 38.2 g of water is:
Since we can dissolve up to 20.9 g of MgCl₂ and we added only 16.2 g, the mixture is homogeneous and we could add 20.9 g -16.2 g = 4.7 g of solute to make it saturated.
(b)
At 800°C, we can dissolve 66.1 g of MgCl₂ in 100 g of water. The mass that we could dissolve in 38.2 g of water is:
Since we can dissolve up to 25.3 g of MgCl₂ and we added only 16.2 g, we could add 25.3 g - 16.2 g = 9.1 g of solute to make it saturated.
Explanation: Si4H10+O2>SiO2+H2O
2Si4H10 + 13O2 = 8SiO2 + 10H2O
Answer:
d = 3.29 g/cm³
Explanation:
Given data:
Density of material = ?
Mass of material = 56.6 g
Volume of material = 17.2 cm³
Solution:
Formula;
d = m/v
d = density
m = mass
v = volume
by putting values,
d = 56.6 g/ 17.2 cm³
d = 3.29 g/cm³
Answer:
Argon 7.89693x10^25 atoms
Gold 4.1949252x10^25 atoms
Carbon Monoxide 34.55149 moles
Potassium oxide 1.6 moles
Calcium 4.4969x10^24 atoms
Explanation:
Its done with dimensional analysis i can not put the full work here because it would look to sloppy
Answer:
Tienes que poner los elementos de las clasificaciones del agua y sus nombres.
Explanation:
no se explicar pero busca las clasificaciones del agua y las pones nada mas.
