Carbon atoms present in 2. 00 g of butane is 8.28 × 10^22.
Molecular weight of C4H10 is = 58.1 grams
Moles of butane = given mass/ molar mass
= 2/58.1
= 0.0344 mol
Multiply the number of moles by Avogadro's number. This will let you obtain the number of butane molecules:
0.0344 x 6.023 x 10^{23} molecules of butane = 2.07 × 10^22 molecules
of butane
Now multiply this number by four (due to four carbon atoms per butane molecule) to obtain the answer:
so, no. of carbon atoms = 4 x 2.07x 10^22 = 8.28x 10^22 atoms.
Thus the no. of carbon atom is 8.28×10^22.
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The decay mode of cesium-137 is beta decay. This means that the cesium-137 decays into a beta particle and a nuclide with the same mass number, but with a charge number that is 1 more than that of cesium.
Therefore, this means Cs-137 decays into an electron and Barium-137, meaning the answer is choice 1.
8 groups, 1 to 7 and most people call group 8 group 0 because the noble gases in group 0 have the outer electron shell full, so for example argon has 18 electrons, so it’s structure is 2.8.8 with its outer shell full. Also the number of the last shell defies what group it’s in, for example sodium is in group 1 so it’s structure is 2.8.1. Hope this helps.
Answer:
H2O molecules are thus able to form an average of 4 H-bonds. H2O has a higher boiling point than NH3 because (i) the H-bonds are stronger and (ii) it contains twice as many H-bonds. H2O has a higher boiling point than HF because it contains twice as many H- bonds, despite these being individually weaker.
Explanation:
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