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Katyanochek1 [597]
3 years ago
13

What acceleration does a 9 N force produce in a 3 kg object? Make sure to show your work. (The 4 steps)​

Physics
1 answer:
Furkat [3]3 years ago
3 0

Answer: 3m/s^2

Explanation:

Given that:

Acceleration of object = ?

Force = 9 N

Mass of object = 3 kg

Since force is the product of the mass of an object and the acceleration by which it moves i.e Force = mass x acceleration

9N = 3kg x acceleration

Acceleration = 9N/3kg

Acceleration = 3m/s^2 (3 metres per second square)

Thus, an acceleration of 3m/s^2 is produced.

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Potential energy is the ability to:
Ymorist [56]

Answer:

potential energy is the ability to do work

8 0
4 years ago
What is Newton's first law of motion​
konstantin123 [22]
Newtons 1st law of motion is law of inertia and this law is either an object at rest stays at rest or an object in motion stays in motion with the same speed and in the same direction unless acted upon by an unbalanced force.
8 0
3 years ago
If there are 1,600 meters in a mile, find the speed of sound in this experiment in units of "miles / hour"
atroni [7]

Answer:

v = 771.75 mile / h

Explanation:

The speed of sound is v = 343 m / s  at T= 20C

the transformation ratios are

     1 mile = 1600 m

     1 h = 3600 s

Let's reduce

    v = 343 m / s (1 mile / 1600 m) (3600 s / 1 h)

    v = 771.75 mile / h

4 0
4 years ago
What is the magnitude of the net force needed to bring a 2110 kg car to rest from 18.1 m/s in 7.0 seconds?
lozanna [386]
Here is what we know:
a = ?, s = ?, u = 18.1m/s, v = zero/rest, t = 7.0s, m = 2110kg

(a = acceleration, s= displacement, u = initial velocity, v = final velocity, t = time and m is mass)

Now we choose a kinematic formula. Since we know v, u and t, we will use the formula: v = u+at and rearrange it so that we can find a.
a = v-u/t
a = 0-18.1/7.0 = -2.5857...
therefore, a = -2.6m/s

We have our acceleration, now let’s find the net force. To find the force we use one of Newtons laws of motion.
We will use Newtons second law since it describes what happens when one or more forces act upon an object.
F = ma
F = (2110kg)(-2.6m/s)
F = -5486 kg
Therefore the net force F = -5486 N
4 0
4 years ago
An electric field of 790,000 N/C points due west at a certain spot. What is the magnitude of the force that acts on a charge of
matrenka [14]

Answer:

-2370000 N force acts on the charge particle    

Explanation:

We have given electric field E = 790000 N/C

Charge q=-3\mu C=-3\times 10^{-6}C

We know that force on any charge particle due to electric field is given by

F=qE, here q ia charge and E is electric field

So force F=-3\times 10^{-6}\times 790000=-2370000N

So -2370000 N force acts on the charge particle  

5 0
3 years ago
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