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adell [148]
3 years ago
15

Write the following as a ratio in simplest form: 2 weeks out of 1 year (52 weeks).

Chemistry
1 answer:
faust18 [17]3 years ago
4 0
2:52 which would simplify to 1:26
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What happens to the motion of molecules when temperature decreases
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Answer:

As the temperature of a solid, liquid or gas increases, the particles move more rapidly.

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3 years ago
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A hypothetical element has an atomic weight of 48.68 amu. It consists of three isotopes having masses of 47.00 amu, 48.00 amu, a
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Answer : The percent abundance of the heaviest isotope is, 78 %

Explanation :

Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i

As we are given that,

Average atomic mass = 48.68 amu

Mass of heaviest-weight isotope = 49.00 amu

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Fractional abundance of heaviest-weight isotope = \frac{x}{100}

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Percentage abundance of lightest-weight isotope = 10 %

Fractional abundance of lightest-weight isotope = \frac{10}{100}

Mass of middle-weight isotope = 48.00 amu

Percentage abundance of middle-weight isotope = [100 - (x + 10)] %  = (90 - x) %

Fractional abundance of middle-weight isotope = \frac{(90-x)}{100}

Now put all the given values in above formula, we get:

48.68=[(47.0\times \frac{10}{100})+(48.0\times \frac{(90-x)}{100})+(49.0\times \frac{x}{100})]

x=78\%

Therefore, the percent abundance of the heaviest isotope is, 78 %

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3 years ago
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ch4aika [34]
The correct answer is (1) one mole of NO2.

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Bond order of n2<br><br>bond order of N2 ​
snow_lady [41]

Answer:

The MO method for N2+ gives the bond order equal to 2.5. But first, we look at the diagram of molecular orbitals for N2 (the bond order for the nitrogen molecule is 3). the N2+ molecule). That is, the bond order for N2+ is 2.5.

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