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zzz [600]
3 years ago
11

A 59 kg physics student is riding her 220 kg Harley at 12 m/s when she has a head-on collision with a 2.1 kg pigeon flying the o

pposite direction at 44m/s. The bird is still on the motorcycle after the collision. How fast is the motorcycle going after the collision?
Physics
1 answer:
IgorLugansk [536]3 years ago
6 0

Answer:

Explanation:

Using conservation of momentum

m_1=59+220=279kg

m_2=2.1kg

U_1=12m/s

U_2=-44m/s

m_1U_1+m_2U_2=(m_1+m_2)V\\\\\frac{278\times 12-2.1\times 44}{279+2.1}=V\\\\V=11.58m/s

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Identify one organism in the chart that is a decomposer
FromTheMoon [43]

Answer:

fungi

Explanation:

6 0
3 years ago
Brayden and Riku now use their skills to work a problem. Find the equivalent resistance, the current supplied by the battery and
Liono4ka [1.6K]

a) 5 \Omega, 1.6 A

b) 6 \Omega, 1.33 A

Explanation:

a)

In this situation, we have two resistors connected in series.

The equivalent resistance of resistors in series is equal to the sum of the individual resistances, so in this circuit:

R=R_1+R_2

where

R_1=4\Omega

R_2=1 \Omega

Therefore, the equivalent resistance is

R=4+1=5 \Omega

Now we can use Ohm's Law to find the current flowing through the circuit:

I=\frac{V}{R}

where

V = 8 V is the voltage supplied by the battery

R=5\Omega is the equivalent resistance of the circuit

Substituting,

I=\frac{8}{5}=1.6 A

The two resistors are connected in series, therefore the current flowing through each resistor is the same, 1.6 A.

b)

In this part, a third resistor is added in series to the circuit; so the new equivalent resistance of the circuit is

R=R_1+R_2+R_3

where:

R_1=4\Omega\\R_2=1\Omega\\R_3=1\Omega

Substituting, we find the equivalent resistance:

R=4+1+1=6 \Omega

Now we can find the current through the circuit by using again Ohm's Law:

I=\frac{V}{R}

where

V = 8 V is the voltage supplied by the battery

R=6\Omega is the equivalent resistance

Substituting,

I=\frac{8}{6}=1.33 A

And the three resistors are connected in series, therefore the current flowing through each resistor is the same, 1.33 A.

3 0
3 years ago
What is the answer to this problem
vredina [299]

420 m of total distance is covered by the skier on travelling from A to D.

Explanation:

As from the picture, it can be seen that first the skier moved from position A to position B. And the distance covered by this movement is 180 m. Then as the skier travels from position B to position C, the distance between these two positions is 140 m from the figure. As distance is a scalar quantity, the direction is not taken into consideration. So only the magnitudes of the distance between those points are added.

Now, the distance between A to B is 180 m and then from B to C is 140 m,  atlast from C to D, the distance is given as 100 m.

So, the total distance will be the sum of all the above found distances. Thus, the total distance will be 180+140+100 = 420 m.

As the question is about distance, so no need to write the direction for it.

Thus, the final answer will be 420 m of total distance is covered by the skier on travelling from A to D.

6 0
3 years ago
Col. John Stapp led the U.S. Air Force Aero Medical Laboratory's research into the effects of higher accelerations. On Stapp's f
Lerok [7]

Answer:

A.a=203.14\ \frac{m}{s^2}

B.s=397.6 m

Explanation:

Given that

speed  u= 284.4 m/s

time t = 1.4 s

here he want to reduce the velocity from 284.4 m/s to 0 m/s.

So the final speed v= 0 m/s

We know that

v= u + at

So now by putting the values

0 = 284.4 -a x 1.4     (here we take negative sign because this is the case of de acceleration)

a=203.14\ \frac{m}{s^2}

So the acceleration  while stopping will be a=203.14\ \frac{m}{s^2}.

Lets take distance travel before come top rest is s

We know that

v^2=u^2-2as

0=284.4^2-2\times 203.14\times s

s=397.6 m

So the distance travel while stopping is 397.6 m.

8 0
3 years ago
Read 2 more answers
Two children stretch a jump rope between them and send wave pulses back and forth on it. The rope is 2.6 m long, its mass is 0.5
Irina-Kira [14]

Answer:

15.13 m/s

Explanation:

The wave speed of the stretched rope can be calculated using the following formula

v = \sqrt{\frac{F_T}{\mu}}

where F_T = 44N is the tension on the rope and \mu = m/L = 0.5 / 2.6 = 0.1923 kg/m is the density of the rope per unit length

v = \sqrt{\frac{44}{0.1923}} = \sqrt{228.8} = 15.13 m/s

6 0
3 years ago
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