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zzz [600]
3 years ago
11

A 59 kg physics student is riding her 220 kg Harley at 12 m/s when she has a head-on collision with a 2.1 kg pigeon flying the o

pposite direction at 44m/s. The bird is still on the motorcycle after the collision. How fast is the motorcycle going after the collision?
Physics
1 answer:
IgorLugansk [536]3 years ago
6 0

Answer:

Explanation:

Using conservation of momentum

m_1=59+220=279kg

m_2=2.1kg

U_1=12m/s

U_2=-44m/s

m_1U_1+m_2U_2=(m_1+m_2)V\\\\\frac{278\times 12-2.1\times 44}{279+2.1}=V\\\\V=11.58m/s

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30grams

Explanation:

If a reaction starts with 30grams then the reaction should end with 30grams.

This in conformity with the law of conservation of mass.

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3 years ago
A 39.3 g glass thermometer reads 22.0oC before it
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Answer:

44.85C

Explanation:

Let the specific heat of glass thermometer be 0.84 J/g°C

Let the specific heat of water be 4.186 j/g °C

Let the water density be 1kg/L

136 mL of water = 0.136L of water = 0.136 kg of water = 136 g of water

Since the change of temperature on the glass thermometer is 43.6 - 22 = 21.6 C. We can then calculate the heat energy absorbed to it:

E = m_gc_g \Delta T = 39.3 * 0.84 * 21.6 = 713.06 J

Assume no energy is lost to outside, by the law of energy conservation, this heat energy would come from water

E = m_wc_w(T - T_w) = 713.06

136*4.186(T - 43.6) = 713.06

T - 43.6 = \frac{713.06}{136*4.186} = 1.25

T = 1.25 + 43.6 = 44.85C

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