A mass weighing 32 pounds stretches a spring 2 feet.
(a) Determine the amplitude and period of motion if the mass is initially released from a point 1 foot above the equilibrium position with an upward velocity of 6 ft/s.
(b) How many complete cycles will the mass have completed at the end of 4 seconds?
Answer:

Period =
seconds
8 cycles
Explanation:
A mass weighing 32 pounds stretches a spring 2 feet;
it implies that the mass (m) = 
m= 
= 1 slug
Also from Hooke's Law
2 k = 32
k = 
k = 16 lb/ft
Using the function:

(because of the initial position being above the equilibrium position)
( as a result of upward velocity)
NOW, we have:

However;
means

also implies that:


Hence, 





Period can be calculated as follows:
= 
=
seconds
How many complete cycles will the mass have completed at the end of 4 seconds?
At the end of 4 seconds, we have:


cycles
Polarized light waves are those that have only one plane of vibration. Polarization is the process by which non-polarized light is converted into polarised light. There are numerous ways to polarise light.
A characteristic of transverse waves called polarisation identifies the geometric angle of the oscillations. A transverse wave's oscillation direction is perpendicular to the wave's motion direction.
given
Only 72.0% of the light's intensity makes it through the sheet and hits another sheet of polarising material. The second sheet lets no light flow through it.
Given that no light passes through the second sheet because both sheets are crossed, the angle the transmission axis of the second sheet makes with the vertical is
θ₂ = θ₁ + 90°
= 31.94° + 90°
= 1 21.94°
for the first sheet and
Icos²θ₁ = I
I/I₀ = 0.72
θ₁ = cos⁻¹√(0.72)
= 31.94°
for the second sheet, respectively. This is because the malus law states that I = Iocos²θ₁ for the first sheet.
To know more about light that is polarized, click on the link below:
brainly.com/question/3092611
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Answer:
0.2854
Explanation:
The Energy stored in coil is given by
U=
L
U=0.565Uo





Apply log: both sides we get


Answer:
the velocity of the car is 30 m/s.
Explanation:
Given;
Centripetal force on the car, F = 900 N
mass of the car, m = 10 kg
diameter of the circular path, d = 20 m
radius of the circular path, r = 10 m
The velocity of the car is calculated as follows;

Therefore, the velocity of the car is 30 m/s.