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sashaice [31]
4 years ago
5

Jami is doing an experiment to find out how temperature slows down or speeds up the sprouting of bean seeds. To prepare for the

experiment, she plans to put soil into three foam cups and place six seeds in each cup. When Jami performs the experiment, which of the following should she keep the same for all of the cups of beans?
I. the amount of sunlight
II. the amount of water
III. the temperature
IV. the amount of fertilizer


A. I, II, and IV only
B. I and III only
C. I and II only
D. II and III only
Physics
2 answers:
natali 33 [55]4 years ago
6 0
Answer: A) I, II, and IV only
----
The things you want to keep the same are the controls. 
Keeping these things the same will help your independent variable, what you're changing (aka temperature), to be the only thing affecting your dependent variable, what you're measuring that usually changes because of the independent variable (aka speed of sprouting), giving you more accurate results.

From your list of choices, notice that the only thing you'll be changing is the III, the temperature. You want the amount of sunlight (I), water (II), and fertilizer (IV) to remain the same, or else those things might affect your final results. You want temperature to be the only thing affecting your final results!
lesya [120]4 years ago
3 0

the answer is A because When performing an experiment, it is important to change only one independent variable at a time.

In[?] this experiment, since Jami wants to see how different temperatures [?]affect sprouting, she must change the temperature, but she should leave the amount of sunlight, water, and fertilizer the same for all of the cups of beans.

If[?] Jami changes two variables—such as temperature and water—at the same [?]time and then finds that some of the beans sprouted faster than others, [?]she will not know which change caused the sprouting to speed up.

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A mass weighing 32 pounds stretches a spring 2 feet. Determine the amplitude and period of motion if the mass is initially relea
grandymaker [24]

A mass weighing 32 pounds stretches a spring 2 feet.

(a) Determine the amplitude and period of motion if the mass is initially released from a point 1 foot above the equilibrium position with an upward velocity of 6 ft/s.

(b) How many complete cycles will the mass have completed at the end of 4 seconds?

Answer:

A = 1.803 ft

Period = \frac{\pi}{2} seconds

8 cycles

Explanation:

A mass weighing 32 pounds stretches a spring 2 feet;

it implies that the mass (m) = \frac{w}{g}

m= \frac{32}{32}

= 1 slug

Also from Hooke's Law

2 k = 32

k = \frac{32}{2}

k = 16 lb/ft

Using the function:

\frac{d^2x}{dt} = - 16x\\\frac{d^2x}{dt} + 16x =0

x(0) = -1        (because of the initial position being above the equilibrium position)

x(0) = -6          ( as a result of upward velocity)

NOW, we have:

x(t)=c_1cos4t+c_2sin4t\\x^{'}(t) = 4(-c_1sin4t+c_2cos4t)

However;

x(0) = -1 means

-1 =c_1\\c_1 = -1

x(0) =-6 also implies that:

-6 =4(c_2)\\c_2 = - \frac{6}{4}

c_2 = -\frac{3}{2}

Hence, x(t) =-cos4t-\frac{3}{2} sin 4t

A = \sqrt{C_1^2+C_2^2}

A = \sqrt{(-1)^2+(\frac{3}{2})^2 }

A=\sqrt{\frac{13}{4} }

A= \frac{1}{2}\sqrt{13}

A = 1.803 ft

Period can be calculated as follows:

= \frac{2 \pi}{4}

= \frac{\pi}{2} seconds

How many complete cycles will the mass have completed at the end of 4 seconds?

At the end of 4 seconds, we have:

x* \frac{\pi}{2} = 4 \pi

x \pi = 8 \pi

x=8 cycles

5 0
3 years ago
light that is polarized along the vertical direction is incident on a sheet of polarizing material. only 87% of the intensity of
nekit [7.7K]

Polarized light waves are those that have only one plane of vibration. Polarization is the process by which non-polarized light is converted into polarised light. There are numerous ways to polarise light.

A characteristic of transverse waves called polarisation identifies the geometric angle of the oscillations. A transverse wave's oscillation direction is perpendicular to the wave's motion direction.

given

Only 72.0% of the light's intensity makes it through the sheet and hits another sheet of polarising material. The second sheet lets no light flow through it.

Given that no light passes through the second sheet because both sheets are crossed, the angle the transmission axis of the second sheet makes with the vertical is

θ₂ = θ₁ + 90°

   = 31.94° + 90°

   = 1 21.94°

for the first sheet and

Icos²θ₁ = I

I/I₀ = 0.72

θ₁ = cos⁻¹√(0.72)

    = 31.94°

for the second sheet, respectively. This is because the malus law states that I = Iocos²θ₁ for the first sheet.

To know more about light that is polarized, click on the link below:

brainly.com/question/3092611

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8 0
2 years ago
It takes 85N of force to accelerate a ball at a rate of 15 m/s². What is the mass of the ball?
Anon25 [30]

Explanation:

F = ma

85 N = m (15 m/s²)

m ≈ 5.7 kg

6 0
3 years ago
At t = 0, a battery is connected to a series arrangement of a resistor and an inductor. At what multiple of the inductive time c
Paraphin [41]

Answer:

0.2854

Explanation:

The Energy stored in coil is given by

U=\frac{1}{2}LI^{2}

U=0.565Uo

(\frac{1}{2} )L(i^{2} )=(0.565)(\frac{1}{2} )L(io^{2} )

(i^{2} )=(0.565)(io^{2} )

(ioe^{-t/T}  )^{2}=(0.565) (io)^{2}

(io)^{2}e^{-2t/T}=(0.565)(io)^{2}

e^{-2t/T}=0.565

Apply log: both sides we get

\frac{-2t}{T}=-0.5709

\frac{t}{T}=0.2854

5 0
4 years ago
If the force of a 10 kg car traveling in a circular path is 900n and the circle has a diameter of 20 m what is the velocity of t
viktelen [127]

Answer:

the velocity of the car is 30 m/s.

Explanation:

Given;

Centripetal force on the car, F = 900 N

mass of the car, m = 10 kg

diameter of the circular path, d = 20 m

radius of the circular path, r = 10 m

The velocity of the car is calculated as follows;

F = \frac{mv^2}{r} \\\\mv^2 = Fr\\\\v^2 = \frac{Fr}{m} \\\\v = \sqrt{\frac{900 \times 10}{10} } \\\\v = 30 \ m/s

Therefore, the velocity of the car is 30 m/s.

3 0
3 years ago
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