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ratelena [41]
3 years ago
8

When 1.82 mole of HCL reacts with excess MnO2, how many moles of Cl2 form?

Chemistry
1 answer:
liubo4ka [24]3 years ago
6 0
The balanced reaction is:

MnO2<span>(s) + 4HCl(aq) → Cl2(g) + MnCl2(aq) + 2H2O(l)
</span>
We are given the amount of hydrochloric acid to be used for the reaction. This will be the starting point for the calculations.

1.82 mol HCl ( 1 mol Cl2 / 4 mol HCl) = 0.46 mol Cl2

Therefore, 0.46 mol of chlorine gas is produced for the reaction of hydrochloric acid and manganese oxide.
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Sugar is easily soluble in water and has a molar mass of 342.30 g/mol. What is the molar concentration of a 259.8 mL aqueous sol
DanielleElmas [232]

Answer:

M=0.822M

Explanation:

Hello,

In this case, given the mathematical definition of molar concentration as the moles of solute divided by the liters of solution:

M=\frac{n}{V}

We can easily compute it by firstly computing the moles of sugar by using its molar mass:

n=73.1g*\frac{1mol}{342.30g} =0.214mol

After that, we compute the concentration by realizing 259.8 mL equals 0.2598 L:

M=\frac{0.214mol}{0.2598L}\\ \\M=0.822mol/L

Or just:

M=0.822M

Considering molar units as mol/L

Best regards.

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Explanation:

In periodic table:

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Transition metals have high densities which increases down the group. However, the increase in density of transition elements of group 12 varies with temperature at a rate that is quite different from other transition elements. Hence the differences in the value of melting points and density changes by only a very small amount as you come down group 12 compared to other groups of transition elements.

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