Answer:
0, l is n-1 always, ml is l to -l
Answer:
4.97 X 10^13 ATOMS OF Zn
Explanation:
how many atoms of zinc are required to weigh 5.4 ng
a nano gram is 10^-9 grams
Zinc has an atomic mass of 65.39 gm/moles
there is an Avogadros number of atoms in a mole
65.39 GRAMS PER MOLE
65.39 g/(6.022 X 10^23)how many atoms of zinc are required to weigh 5.4 ng
GRAMS PER ATOM
1.086 GRAMS PER 1O^22 ATOMS
1 atom of Zn weighs 1.086 X 10^9 X 1O^-22 n grm=
1,086 X 10^-13 n gm
Y tines 1.086 X 10^-13 = 5.4 n gm
Y = 5.4/ (1.086 X 10^-13) =
4.97 X 10^13 ATOMS OF Zn
CHECK
(4.97 X 10^13 ) X 65.39 gm/(6.022 X 10^23) =
5.397 X 10^-9 =
5.4 n g
That is a graph read both sides and you see speed and distance which must mean that someone is graphing peoples speed.
The pressure of Carbon Dioxide in the bottles lower and the CO2 diffuses out from the drink.. Hence bubbles are formed.. :)
Mol of Na =
=
= 0.13 mol
# atoms of Na = mol × avogadro's constant
= 0.13 mol × [6.02 × 10²³]
= 7.83 × 10²²