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faltersainse [42]
3 years ago
6

20 POINTS PLEASE ANSWER

Chemistry
1 answer:
Sever21 [200]3 years ago
8 0

c. It decreases when going down a group.  

<u>Explanation:</u>

Ionization energy is the energy needed to remove an electron from the neutral gaseous atom.

It is represented in kJ/mol.

As we move down the group the ionization energy decreases, since the outermost electrons are far away from the nucleus of an atom and so attains greater shielding effect. They encounter a weaker force of attraction to the +ve charge on the nucleus. And so, Ionization energy decreases from top to bottom in a group.

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What did Thomas Young, Max planck and Albert Einstein contribute towards the nature of light?
Lera25 [3.4K]

The contribution to the nature of light-

Thomas Young - wave nature of light (double-slit experiment)

Max Planck - E = hv

Albert Einstein - a quantum theory of light

Thomas Young proposed the most important double-slit experiment which shows that light acts like a wave and shows the pattern of interferences.

Max Planck proposed that light is proportional to frequency. He gave the equation, E = hv, where E is the energy of light, h is Planck's constant, and v is the frequency.

Albert Einstein proposed the quantum theory of light. He determined that light exists in discrete quanta of energy called photons.

To learn more about the nature of light, visit: brainly.com/question/4423091

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2 years ago
A sample of urea contains 1.121 g of N, 0.161 g of H, 0.48 g of C, and 0.64 g of O. What is the empirical formula of urea?
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Explanation:

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What is the molecular formula for water?
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5 0
2 years ago
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Burka [1]
Answer- 400 grams of AlCl3 is the maximum amount of AlCl3 produced during the experiment.

Given - Number of moles of Al(NO3)3 - 4 moles
Number of moles of NaCl - 9 moles
Find - Maximum amount of AlCl3 produced during the reaction.
Solution - The complete reaction is - Al(NO3)3 + 3NaCl --> 3NaNO3 + AlCl3
To find the maximum amount of AlCl3 produced during the reaction, we need to find the limiting reagent.
Mole ratio Al(NO3)3 - 4/1 - 4
Mole ratio NaCl - 9/3 - 3
Thus, NaCl is the limiting reagent in the reaction.
Now, 3 moles of NaCl produces 1 mole of AlCl3
9 moles of NaCl will produce - 1/3*9 - 3 moles.
Weight of AlCl3 - 3*133.34 - 400 grams
Thus, 400 grams of AlCl3 is the maximum amount of AlCl3 produced during the experiment.
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