r1 = 5*10^10 m , r2 = 6*10^12 m
v1 = 9*10^4 m/s
From conservation of energy
K1 +U1 = K2 +U2
0.5mv1^2 - GMm/r1 = 0.5mv2^2 - GMm/r2
0.5v1^2 - GM/r1 = 0.5v2^2 - GM/r2
M is mass of sun = 1.98*10^30 kg
G = 6.67*10^-11 N.m^2/kg^2
0.5*(9*10^4)^2 - (6.67*10^-11*1.98*10^30/(5*10^10)) = 0.5v2^2 - (6.67*10^-11*1.98*10^30/(6*10^12))
v2 = 5.35*10^4 m/s
PART A)
Here we know that
potential difference across the wire is
resistance of wire is
now by ohm's law
Part b)
Power rating is defined as rate of electrical energy
it is defined as
now we have
The mass of the cold water, given the data from the question is 500 g
<h3>Data obtained from the question</h3>
- Mass of warm water (Mᵥᵥ) = 200 g
- Temperature warm water (Tᵥᵥ) = 75 °C
- Temperature of cold water (T꜀) = 5 °C
- Equilibrium temperature (Tₑ) = 25 °C
- Specific heat capacity of the water = 4.184 J/gºC
- Mass of cold water (M꜀) =?
<h3>How to determine the mass of the cold water </h3>
Heat loss = Heat gain
MᵥᵥC(Tᵥᵥ – Tₑ) = M꜀C(Tₑ – T꜀)
200 × 4.184 (75 – 25) = M꜀ × 4.184(25 – 5)
41840 = M꜀ × 83.68
Divide both side 83.68
M꜀ = 41840 / 83.68
M꜀ = 500 g
Learn more about heat transfer:
brainly.com/question/6363778
#SPJ1
Answer:
Real image
Explanation:
The picture is real, but it is reversed and tiny. An picture generated by a pinhole camera has certain features. As compared item, the image created by a pinhole camera is normally pretty small and looks reversed both on the vertically and horizontally axis.
