Answer:
The second and third
Step-by-step explanation:
To factor quadratic equations of the form ax^2+bx+c=y, you must find two values, j and k, which satisfy two conditions.
jk=ac and j+k=b
The you replace the single linear term bx with jx and kx. Finally then you factor the first pair of terms and the second pair of terms. In this problem...
2k^2-5k-18=0
2k^2+4k-9k-18=0
2k(k+2)-9(k+2)=0
(2k-9)(k+2)=0
so k=-2 and 9/2
k=(-2, 4.5)
5y-30=-5y+30
add 30 to both sides
5y = -5y+60
add 5y to both sides
10y = 60
divide both sides by 10
y = 6
<em>hope this helps!</em>
Answer: the answer is a
Step-by-step explanation:
