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san4es73 [151]
3 years ago
10

Factor completely, then place the answer in the proper location on the grid. 21a^2- 57a+30

Mathematics
1 answer:
aev [14]3 years ago
6 0

Answer:

(a^2 - 10)(3+7)

Step-by-step explanation:

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Please help!!!!!!!!!!
horrorfan [7]

Answer:

sqrt 2

Step-by-step explanation:

4 0
2 years ago
The total number of markers that Nancy has if she gives away 2/5 of her m markers to Amy
Archy [21]

Answer:

she has 3/5 left


7 0
3 years ago
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Plzz help me to solve this qns please
tatiyna

9514 1404 393

Answer:

  ₹14000

Step-by-step explanation:

Let c represent the cost price, and m represent the marked price.

  c × (1 +40%) = m

  m × (1 -15%) - c = ₹1900

Using the first expression for m, the second equation becomes ...

  1.40c×0.85 -c = ₹1900

  0.19c = ₹1900

  c = ₹1900/0.19 = ₹10000

Then the marked price was ...

  m = 1.40c = 1.40×₹10000 = ₹14000

The marked price was ₹14000.

_____

The selling price was ₹11900.

7 0
3 years ago
What is the circumference of a circle with a diameter of 190mm?
MrMuchimi

Answer:

it's 502.6548246

Step-by-step explanation:

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7 0
3 years ago
Please help The dilation DO,2.5 is applied to triangle ABC below. Use the dilation of triangle ABC and its image to prove that t
viva [34]
A dilation D_{O,\,k} is a dilation with a scale factor, k centered at the origin.

A scale factor, k means that the distance of the image from the the center of dilation is k times the distance of the pre-image from the center of dilation and the size of the image is k times the size of the pre-image.

Given triangle ABC with vertices A(-2, 2), B(1, 2) and C(1, -1), a dilation D_{O,\,k} will result in the image with vertices A'2.5(-2, 2) = A'(-5, 5), B'2.5(1, 2) = B'(2.5, 5) and C'2.5(1, -1) = C'(2.5, -2.5)

Now, consider line AC, the equation of the line is given by

\frac{y-2}{x-(-2)} = \frac{-1-2}{1-(-2)} \\ \\ \Rightarrow \frac{y-2}{x+2} = \frac{-3}{1+2} = \frac{-3}{3} =-1 \\ \\ \Rightarrow y-2=-(x+2)=-x-2 \\ \\ \Rightarrow y=-x

Notice that line y = -x is a line passing through the origin which is the center of dilation.

Consider line A'C', the equation of the line is given by

\frac{y-5}{x-(-5)} = \frac{-2.5-5}{2.5-(-5)} \\ \\ \frac{y-5}{x+5} = \frac{-7.5}{2.5+5} = \frac{-7.5}{7.5} =-1 \\ \\ \Rightarrow y-5=-(x+5)=-x-5 \\ \\ \Rightarrow y=-x

As an be seen the line AC and the line A'C' is the same line.
4 0
3 years ago
Read 2 more answers
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