The molecular weight of Mg(OH)2 : 58 g/mol
<h3>Further explanation</h3>
Given
Mg(OH)2 compound
Required
The molecular weight
Solution
Relative atomic mass (Ar) of element : the average atomic mass of its isotopes
Relative molecular weight (M) : The sum of the relative atomic mass of Ar
M AxBy = (x.Ar A + y. Ar B)
So for Mg(OH)2 :
= Ar Mg + 2 x Ar O + 2 x Ar H
= 24 g/mol + 2 x 16 g/mol + 2 x 1 g/mol
= 24 + 32 + 2
= 58 g/mol
The mass of the product is <em>98.78 g.</em>
The word equation is
aluminum + chlorine → product
20.00 g + 98.78 g → <em>x</em> g
If each reactant is completely consumed, the <em>Law of conservation of Mass </em>tells us the mass of the product must be 98.78 g.
Answer:
C. Different heights of holes in the container
Explanation:
The independent variable is the variable that changes. So the independent variable is C because the heights of the holes change.
Answer:
5.90, 11.8, 47.2
Explanation:
Let’s remove the parentheses and write the formula as MgCl₂O₈.
We see that 1 mol Mg(ClO₄)₂ contains 1 mol Mg atoms, 2 mol Cl atoms, and 8 mol O atoms.
∴ 
∴ Mg, Cl, O = 5.90, 11.8, 47.2
