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evablogger [386]
3 years ago
13

What is one advantage of using primary source when doing research on an experiment

Physics
1 answer:
kenny6666 [7]3 years ago
6 0

the benefit of direct contact, through a survey or interview

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Electronegativity increases when atoms ___
notka56 [123]

your answer is.....

D. have a large atomic radius

although they also increase going from left to right so if D is incorrect, B might be your answer. it depends on context of the lesson.

8 0
3 years ago
How heat is conducted along a metal bar?
nikdorinn [45]

Answer:

If one end of a metal bar is heated, the atoms at that end vibrate more than the atoms at the cold end. The vibration spreads along the bar from atom to atom.

Explanation:

The spread of heat in this way is called conduction. Metals are good conductors of heat.

3 0
3 years ago
Read 2 more answers
What is the magnitude of the electric force between a proton and an electron when they are at a distance of 4.09 angstrom from e
Zinaida [17]

Answer:

F=1.38*10^{-9}N

Explanation:

According to Coulomb's law, the magnitude of the electric force between two point charges is directly proportional to the product of the magnitude of both charges and inversely proportional to the square of the distance that separates them:

F=\frac{kq_1q_2}{d^2}

Here k is the Coulomb constant. In this case, we have q_1=-e, q_2=e and d=4.09*10^-10m. Replacing the values:

F=\frac{8.99*10^{9}\frac{N\cdot m^2}{C^2}(-1.6*10^{-19}C)(1.6*10^{-19}C)}{(4.09*10^{-10})^2}\\F=-1.38*10^{-9}N

The negative sign indicates that it is an attractive force. So, the magnitude of the electric force is:

F=1.38*10^{-9}N

5 0
3 years ago
After being accelerated through a potential difference of 5.33 kv, a singly charged carbon ion (12c) moves in a circle of radius
LekaFEV [45]
I'm stuck on the same question, as well :(
4 0
3 years ago
A guitar string with a linear mass density of 2.0 g/m is stretched between two vertical rods that are 65 cm apart. The string ho
Rudiy27

Answer:

717 Hz

Explanation:

<u>solution:</u>

The wave with three antinodes has m = 3. Thus, f_3 = 3f_1 and so the fundamental frequency of the string is  

f_1 =f_3/3

    =430 Hz/3

    =143 Hz

Thus, the frequency of the fifth harmonic is

f_5 = 5*f_1

      = 5*143 Hz

     = 717 Hz

7 0
3 years ago
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