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evablogger [386]
3 years ago
13

What is one advantage of using primary source when doing research on an experiment

Physics
1 answer:
kenny6666 [7]3 years ago
6 0

the benefit of direct contact, through a survey or interview

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A 5.0 kg wooden block is placed at an adjustable inclined plane. what is the angle of incline above which the block will start t
Aleks [24]
The value of the angle of the incline \theta at which the block starts to slide is the angle at which the component of the weight parallel to the incline becomes equal to the frictional force that keeps the block on the incline:
mg \sin \theta = \mu N
where the term on the left is the component of the weight parallel to the incline, and the term on the right is the frictional force, which is the product between the coefficient of friction \mu and the normal reaction of the incline N.

The normal reaction of the incline, N, is equal to the component of the weight perpendicular to the incline:
N=mg \cos \theta
Therefore, the initial equation becomes
mg \sin \theta = \mu mg \cos \theta
From which we find
\tan \theta = \mu
\theta = \arctan \mu

For angles above this value, the block will start sliding down, otherwise the block will stay on the incline.

3 0
3 years ago
The microwave in your kitchen operates at 2,358,000 Hz. If the speed of light is 300,000,000 m/s, what is the wave’s wavelength?
Novosadov [1.4K]

Answer:

wavelength = speeed / frequency

= 300,000,000 / 2358000

= 300 / 2.358

= 127.2 m

5 0
4 years ago
Complete the following:
Serga [27]

Answer:

the light will reflect parallel to the principal axis

8 0
2 years ago
A 1000 kg car’s velocity increases from 5 m/s to 10 m/s. What is the change to the car’s kinetic energy? Show your work.
katen-ka-za [31]

Answer:

k. e. = 1/2 mv^2

1/2 * 1000 * (5)^2

1/2 * 1000 * 25

12500 joules

k. e. = 1/2 mv^2

1/2 * 1000 * (10)^2

1/2 * 1000 * 100

50000

change in k. e. = final - initial

50000 - 12500

= 37500 joules

hope it helps you

3 0
3 years ago
Calculate the wavelength associated with electrons moving with p.d of 1500v
Artist 52 [7]

Answer:

3.16X10∧-11 m

Explanation:

1/2 mv2 = qV (KE = Electric potential energy)

velocity = √2qV/m = √( 2X 1.6X10∧-19 X 1500/9.11X10∧-31)

2.3X10∧7m/s

now use De Broglie equation

λ = h/mv

= 6.62X10∧-34/( 9.11X10∧-31 X 2.3X10∧7)

3.16 X 10∧-11 m

or

use the above equations and substitute to get the final eqiation

λ = h/√(2mqV) = 3.16X 10∧-11 m

4 0
3 years ago
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