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VARVARA [1.3K]
2 years ago
9

Hãy kể tên, kí hiệu, đơn vị một số đại lượng Vật Lý mà em đã học ở lớp 10, 11?

Physics
1 answer:
wariber [46]2 years ago
7 0
I’m not Vietnamese but I think your asking for this, for people who understand Vietnamese pls help them :d

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Walk in a straight line. Now stop. Did you accelerate? Explain
Brums [2.3K]

Answer;

It's about acceleration, right?

4 0
3 years ago
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A 3.0 kg box is sliding along a frictionless horizontal surface with a speed of 1.8 m/s when it encounters a spring. (a) Determi
krok68 [10]

Answer:

a) k = 2231.40 N/m

b) v = 0.491 m/s

Explanation:

Let k be the spring force constant , x be the compression displacement of the spring and v be the speed of the box.

when the box encounters the spring, all the energy of the box is kinetic energy:

the energy relationship between the box and the spring is given by:

1/2(m)×(v^2) = 1/2(k)×(x^2)

    (m)×(v^2) = (k)×(x^2)

a) (m)×(v^2) = (k)×(x^2)

                 k = [(m)×(v^2)]/(x^2)

                 k = [(3)×((1.8)^2)]/((6.6×10^-2)^2)

                 k = 2231.40 N/m

Therefore, the force spring constant is 2231.40 N/m

b) (m)×(v^2) = (k)×(x^2)

             v^2 = [(k)(x^2)]/m

                 v =  \sqrt{ [(k)(x^2)]/m}

                 v = \sqrt{ [(2231.40)((1.8×10^-2)^2)]/(3)}

                    = 0.491 m/s

8 0
2 years ago
Read 2 more answers
PLEASE HELPPPP!!!!
Tresset [83]

you will hear a higher pitch due to a higher frequency.

3 0
3 years ago
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Please help on this one?
qwelly [4]

Answer:

D. An image that is smaller than the object and is behind the mirror

5 0
3 years ago
Three balls of equal mass are fired simultaneously with equal speeds from the same height h above the ground. Ball 1 is fired st
pantera1 [17]

Answer:

d) v1 = v2 = v3

Explanation:

This can be answered using conservation of energy. We calculate the mechanical energy E=K+U (sum of kinetic and gravitational potential energies) at the original and final points, and impose they are equal.

At the original point we have, for the three balls:

E_i=K_i+U_i=\frac{mv_i^2}{2}+mgh_i=\frac{mv^2}{2}+mgh

At the final point we have, for the three balls:

E_f=K_f+U_f=\frac{mv_f^2}{2}+mgh_f=\frac{mv_f^2}{2}

Since we have E_i=E_f, and E_i is the same for all balls, then E_f is the same for all balls, which means that v_f, the final velocity, is the same for all balls.

4 0
3 years ago
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