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Montano1993 [528]
2 years ago
14

3

Physics
1 answer:
vovangra [49]2 years ago
4 0
Your answer is. D. 10÷60 = 1.66km/hr
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19.A 20 kg sign is pulled by a horizontal force such that the single rope (originally vertical) holding the sign makes an angle
Andreyy89

Answer:

A)T=209.94N

B) F=75.24N

Explanation:

Using the free body diagram and according to Newton's first law, we have:

\sum F_y=Tcos(21^\circ)-mg=0(1)\\\sum F_x=F-Tsin(21^\circ)=0(2)

A) Solving (1) for T:

T=\frac{mg}{cos(21^\circ)}\\T=\frac{20kg(9.8\frac{m}{s^2})}{cos(21^\circ)}\\T=209.94N

B) Solving (2) for F:

F=Tsin(21^\circ)\\F=(209.94N)sin(21^\circ)\\F=75.24N

8 0
3 years ago
Answer those 2 questions.
Tanya [424]

Answer:

Q1: c

Q2: a

Explanation:

you can tell the factors by looking at the formulas for kinetic and potential energy

for question 1  look at the formula for kinetic energy

KE=\frac{1}{2} mv^{2}

the variables needed in order to calculate an object's kinetic energy are mass and velocity.

hence, when mass and velocity changes, kinetic energy changes, showing that mass and velocity are the factors affecting kinetic energy

same thing for the second question

PE = mgh

as g (acceleration due to gravity) is considered constant (10 m/s^{2} ) it will not be considered as a factor

and thus, the factors affecting potential energy are mass and height

8 0
3 years ago
Please help me this is a test and it needs to be done in a few​
Amanda [17]

Answer:

I think A because astroids are stronger than a crash. Hope I helped! :)

Explanation:

7 0
3 years ago
Read 2 more answers
A sealed 26-m3 tank is filled with 6000 moles of oxygen gas (O2) at an initial temperature of 270 K. The gas is heated to a fina
TiliK225 [7]

Answer:

The final pressure of oxygen gas is 8.33 atm.

Explanation:

From the given data

V=26 m^3 or 26000 L

T1=270K

T2=440K

n1=6000 moles

R=0.0821 L.atm/molK

Now from the ideal gas equation

P_2V_2=nRT_2\\P_2=\frac{nRT_2}{V_2}\\P_2=\frac{6000*0.0821*440}{26000}\\\\P_2=8.33 atm\\

As the options given are not defined in which unit thus the final pressure of oxygen gas is 8.33 atm.

<em>*The options are provided for a different question where </em>

3 0
4 years ago
A rock is dropped from a vertical cliff. The rock takes 3.00 s to reach the ground below the cliff. A second rock is thrown vert
Phantasy [73]

Answer:

Velocity v= 12.25 \frac{m}{s}

Explanation:

The first rock dropped give the distance Y in meters

Y_{f}=Y_{o}+v_{o}*t +\frac{1}{2}*a*t^{2}\\   Y_{f}=\frac{1}{2}* 9.8 \frac{m}{s^{2} }* 3^{2}   \\Y_{f}=44.1 m

Now the motion of the second rock the time change so to know the velocity

Y_{f}= Y_{o} +v_{o}*t +\frac{1}{2}*a *t^{2} \\v_{o}*t= -Y_{f} +\frac{1}{2} *a*t^{2} \\v_{o} =\frac{-44.1 +0.5 * 9.8* s^{2} }{2} \\v_{o}=  12.25 \frac{m}{s}

7 0
3 years ago
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