A 10.0 mL sample of a 2.5 M NaCl solution is diluted to 25.8 mL. What is the new concentration?

Chemistry

1 answer:

Naya [18.7K]3 years ago

4 0

Answer:

$C_2=0.97M$

Explanation:

Hello,

In this case, for dilution process, we can notice that the initial moles remain the same once the dilution is completed, therefore, both concentration and volume change considering:

$n_1=n_2\\\\V_1C_1=V_2C_2$

In such a way for the given final volume, the resulting concentration is noticed to be:

$C_2=\frac{V_1C_1}{V_2} =\frac{10mL*2.5M}{25.8mL}\\ \\C_2=0.97M$

This is supported by the fact that the higher the volume the lower the concentration.

Best regards.

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