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bagirrra123 [75]
3 years ago
12

What is the basic of an organic molecule

Chemistry
2 answers:
julia-pushkina [17]3 years ago
7 0
<span>proteins, carbohydrates, lipids and nucleic acids.</span>
Deffense [45]3 years ago
4 0
Organic molecules<span> are the </span>molecules<span> of life and are built around chains of carbon atoms that are often quite long. There are four main groups of </span>organic molecules<span>that combine to build cells and their parts: carbohydrates, proteins, lipids, and nucleic acids.</span><span>What is the basic of an organic molecule

</span>
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A hypothetical element has three main isotopes with mass numbers of 51, 53, and 54. If 15.00% of the isotopes have a mass number
Eva8 [605]

Answer: 53.25

Explanation: Please see attachment for explanation. Thanks.!

5 0
3 years ago
For the vaporization reaction Br2(l) → Br2(
oksian1 [2.3K]
    The  temperature  at   which  the  process  be   spontaneous  is  calculated  as  follows

delta  G  =  delta H  -T delta S

let  delta G  be =0

therefore  delta H- T  delta s =0

therefore  T=  delta  H/  delta  S
convert  31   Kj  to  J  =  31  x1000=  31000 j/mol

T=31000j/mol /93 j/mol.k =333.33K


3 0
3 years ago
Question 3) A 1.00 L buffer solution is 0.250 M in HF and 0.250 M in LiF. Calculate the pH of the solution after the addition of
Masja [62]

The pH of the solution after adding 0.150 moles of solid LiF is 3.84

<u>Explanation:</u>

We have the chemical equation,

HF (aq)+NaOH(aq)->NaF(aq)+H2O

To find how many moles have been used in this

c= n/V=> n= c.V

nHF=0.250 M⋅1.5 L=0.375 moles HF

Simillarly

nF=0.250 M⋅1.5 L=0.375 moles F

nHF=0.375 moles - 0.250 moles=0.125 moles

nF=0.375 moles+0.250 moles=0.625 moles

[HF]=0.125 moles/1.5 L=0.0834 M

[F−]=0.625 moles/1.5 L=0.4167 M

To determine the problem using the Henderson - Hasselbalch equation

pH=pKa+log ([conjugate base/[weak acid])

Find the value of Ka

pKa=−log(Ka)

pH=−log(Ka) +log([F−]/[HF]

pH= -log(3.5 x 10 ^4)+log(0.4167 M/0.0834 M)

pH=-log(3.5 x 10 ^4)+log(4.996)

pH= -4.54+0.698

pH=-(-3.84)

pH=3.84

The pH of the solution after adding 0.150 moles of solid LiF is 3.84

5 0
3 years ago
Platinum crystallizes with the face-centered cubic unit cell. The radius of a platinum atom is 139 pm. Calculate the edge length
horrorfan [7]

Answer:

Length = 393pm, Density = 21.3 g/cm^3.

Explanation:

From the question above, we have the following parameters or data which is going to aid in solving the above Question.

=> The radius of a platinum atom = 139 pm.

Therefore, the length can be calculated by making use of the formula given below:

Length = 2 √( 2r) = 2 × √ (2 × 139 × 10^-12m ) = 393 × 10^-10 m = 393pm.

The density can be calculated by making use of the chemical formula given below:

Density = mass ÷ volume = (195.064/ 6.02 × 10^23) ÷ (3.93 × 10^-10/ 10^-2) = 21.3 g/cm^3.

3 0
2 years ago
Morphine has the formula c17h19no3. it is a base and accepts one proton per molecule. it is isolated from opium. a 0.685 −g samp
kotykmax [81]
2 C₁₇H₁₉NO₃ + H₂SO₄ → Product
Moles of H₂SO₄ = M x V(liters) = 0.0116 x 8.91/1000 = 1.033 x 10⁻⁴ mole 
moles of morphine = 2 x moles of H₂SO₄ = 2.066 x 10⁻⁴
Mass of morphine = moles x molar mass of morphine = 2.066 x 10⁻⁴ x 285.34 
                             = 0.059 g
percent morphine = \frac{mass of morphine}{mass of opium} x 100
                             = \frac{0.059}{0.685} x 100 = 8.6 %   
7 0
3 years ago
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