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3 years ago

What will happen if water is deionized

1 answer:

4 0

If water is deionized and it is consumed, it may cause people to urinate more and eliminate more electrolytes from the body.

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How many liters of h2 would be formed at 684 mm hg and 13 ∘c if 21.0 g of zinc was allowed to react?

Black_prince [1.1K]

Answer is 8.422 L.
The solving method as the attached pdf.

Download pdf

8 0

4 years ago

Consider the reaction that occurs when copper is added to nitric acid. Cu(s)+4HNO3(aq) ----> Cu(NO3)2(aq)+2NO2(g)+2H2O(I). Wh

alexira [117]

Answer:

Explanation:

We can use oxidation numbers to figure out what is happening with the electrons.

$\rm \stackrel{\hbox{0}}{\hbox{Cu}} + 4H\stackrel{\hbox{+5}}{\hbox{N}}O_{3} \longrightarrow \, \stackrel{\hbox{2+}}{\hbox{Cu}}(NO_{3})_{2} + 2\stackrel{\hbox{+4}}{\hbox{N }}O_{2} + 2H_{2}O$

The oxidation number of Cu increases from 0 to +2 in Cu(NO₃)₂. The copper has gained two positive charges, so it has lost two electrons. It has been oxidized, so it is the reducing agent.

NO₃⁻ is wrong. The oxidation number of N decreases from +5 in NO₃⁻ to +4 in NO₂, so it has been reduced. It is the oxidizing agent.

Cu(NO₃)₂ and NO₂ are wrong. They are the products of the reaction. They cannot be either oxidizing or reducing agents in this reaction

4 0

4 years ago

Read 2 more answers

A student pushes against a wall with 30 Newton’s of force and the wall does not move

uysha [10]

Answer:

you can't go through a solid unless you broke the atoms in the wall

8 0

3 years ago

At a certain temperature, 0.700 mol SO3 is placed in a 3.50 L container. 2SO3(g)↽−−⇀2SO2(g)+O2(g) At equilibrium, 0.180 mol O2 i

Anestetic [448]

Answer: The value of $K_c$ for the given chemical equation is 0.0457.

Explanation:

Given values:

Initial moles of $SO_3$ = 0.700 moles

Volume of conatiner = 3.50 L

The given chemical equation follows:

$2SO_3(g)\rightleftharpoons 2SO_2(g)+O_2(g)$

I: 0.700

C: -2x +2x x

E: 0.700-2x 2x x

Equilibrium moles of $O_2$ = x = 0.180 moles

Equilibrium moles of $SO_2$ = 2x = $(2\times 0.180)=0.360moles$

Equilibrium moles of $SO_3$ = 0.700 - 2x = $0.700-(2\times 0.180)=0.340moles$

Molarity is calculated by using the equation:

$Molarity=\frac{Moles}{Volume}$

So,

$[SO_3]_{eq}=\frac{0.340}{3.50}=0.0971M$

$[SO_2]_{eq}=\frac{0.360}{3.50}=0.103M$

$[O_2]_{eq}=\frac{0.180}{3.50}=0.0514M$

The expression of $K_c$ for above equation follows:

$K_c=\frac{[SO_2]^2[O_2]}{[SO_3]^2}$

Plugging values in above expression:

$K_c=\frac{(0.0971)^2\times 0.0514}{(0.103)^2}\\\\K_c=0.0457$

Hence, the value of $K_c$ for the given chemical equation is 0.0457.

3 0

3 years ago

A biochemist carefully measures the molarity of magnesium ion in 47, mL of cell growth medium to be 97. ??. Unfortunately, a car

serg [7]

Complete Question

The complete question is shown on the first uploaded image

Answer:

Answer: 760 uM

Explanation:

the addition of solvent to a solution in a such away that the volume of the solution increases and the concentration decreases is a process know as dilution

The concentration and the volume of the dilute and concentrated solution are given below as follows

$C_{1}V_{1}$ $= C_{f}V_{f}$

Concentrated solution Dilute solution

Given that M1 = 97.0uM

V1 = 47.0 mL

V2 = 6.0 mL

M2 = ?

Therefore M1V1 = M2V2

M2 = M1V1/V2

M2 = (97*47)/6

M2 = 760 uM

Answer: 760 uM

5 0

4 years ago

What will happen if water is deionized​

What will happen if water is deionized