A heat engine is operating between 287 c and 32 c. if the engine extracted 400 mj of energy from fuel, 4109.6 Jews mj of energy could be used as mechanical energy
Using the temperatures, a heat engine's efficiency is determined (lowest and highest).
The ratio of the system's provided heat to the desired work is considered the system efficiency. An engine's efficiency ranges from 0 to 1.
The efficiency of the engine is 27%, or 0.27. Since the heat was turned down due to the 3000 gems, we must find productive employment. Heat input and network efficiency are connected. That is the line. Qc was rejected by two W plus heat, leading to Qh. The cost of networking is composed of Nita W and Nita Qc. The network completed is identical to Nita. Q C is split into two halves. As a result, we must divide our efficiency, which is 0.27, by 3000. The engine's work is represented by this. Let's calculate the result of 0.27 multiplied by 3000 divided by 1. 1109 and 0.6 gems are the answer. He rejected our quote, which is +110 9.6 plus three thousand. 4109.6 Jews is quite close to the heat input.
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"<span>The amount of space that a sample of matter takes up" is the one among the following choices given in the question that best defines volume. The correct option among all the options that are given in the question is the third option or option "C". I hope that this is the answer that has actually come to your desired help.</span>
Answer:
a. 340.13 m/s b. 680.26 m/s c. our wavelength doubles
Explanation:
a. speed of wave, v = fλ were f = frequency = 301 Hz and λ = wavelength = 1.13 m.
v = fλ = 301 Hz × 1.13 m = 340.13 m/s
b. If we double the frequency then f = 2 × 301 Hz = 602 Hz
v = fλ = 602 Hz × 1.13 m = 680.26 m/s
c. If the speed of the wave is still 340.13 m/s, if we cut the frequency in half, then frequency now equals f = 301 Hz/2 = 150.5 Hz.
Since v = fλ,
λ = v/f = 340.13 m/s ÷ 150.5 Hz = 2.26 m.
Since our initial wavelength λ₀ = 1.13 m,
λ/λ₀ = 2.26 m/1.13 m = 2.
So, λ = 2λ₀ our wavelength doubles
Answer:
D=1.54489 m
Explanation:
Given data
S=6.10 mm= 0.0061 m
To find
Depth of lake
Solution
To find the depth of lake first we need to find the initial time ball takes to hit the water.To get the value of time use below equation
So ball takes 0.035sec to hit the water
As we have found time Now we need to find the final velocity of ball when it enters the lake.So final velocity is given as
Since there are (4.50-0.035) seconds left for (ball) it to reach the bottom of the lake
So the depth of lake given as: