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Airida [17]
4 years ago
9

The takeoff speed for an airbus a320 jetliner is 82 m/s . velocity data measured during takeoff are as follows: t(s) vx(m/s) 0 0

10 23 20 46 30 69 part a what is the jetliner's acceleration during takeoff, in m/s2? express your answer using two significant figures. a = m/s2 submitmy answersgive up part b what is the jetliner's acceleration during takeoff, in g's? express your answer using two significant figures. a = g submitmy answersgive up part c at what time do the wheels leave the ground? express your answer using two significant figures. tf = s submitmy answersgive up part d for safety reasons, in case of an aborted takeoff, the length of the runway must be three times the takeoff distance. what is the
Physics
1 answer:
bulgar [2K]4 years ago
6 0

The table is:

t(s)  vx(m/s)

0     0

10    23

20   46

30   69

a) from the data in the table, we observe that the acceleration is constant (because the rate of change in velocity is the same for each time interval of 10 seconds), so we can choose just one interval and calculate the acceleration as the ratio between the change in velocity and the change in time. Taking the first interval, we find

a=\frac{\Delta v_x}{\Delta t}=\frac{23 m/s-0}{10s -0}=2.3 m/s^2


b) To find the jet's acceleration in g's, we just need to divide the acceleration in m/s^2 by the value of g, the acceleration of gravity (9.81 m/s^2), so we find

a_g=\frac{a}{g}=\frac{2.3 m/s^2}{9.8 m/s^2}=0.23 g


c) the wheels leave the ground when the jet reaches its take-off velocity, which is 82 m/s.

At t=0s, the velocity of the jet is 0. We know that the acceleration is constant (a=2.3 m/s^2), so we can find the time t at which the jet reaches a velocity vf=82 m/s by using the equation

v_f = v_i +at

Re-arranging and substituting numbers, we find

t=\frac{v_f}{a}=\frac{82 m/s}{2.3 m/s^2}=35.65 s

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Answer:

Gravitational Potential Energy = mgh

Explanation:

As the miner moves down, the GPE changes because the height changes.

Gravitational Potential Energy = mgh


8 0
3 years ago
Violet light of wavelength 405 nm ejects electrons with a maximum kinetic energy of 0.890 eV from a certain metal. What is the b
AleksandrR [38]

Answer:

  Ф = 2.179 eV

Explanation:

This exercise has electrons ejected from a metal, which is why it is an exercise on the photoelectric effect, which is explained assuming the existence of energy quanta called photons that behave like particles.

            E = K + Ф

the energy of the photons is given by the Planck relation

            E = h f

we substitute

           h f = K + Ф

           Ф= hf - K

the speed of light is related to wavelength and frequency

            c = λ f

            f = c /λ

            Φ = \frac{hc}{\lambda } - K

let's reduce the energy to the SI system

            K = 0.890 eV (1.6 10⁻¹⁹ J / 1eV) = 1.424 10⁻¹⁹ J

calculate

           Ф = 6.63 10⁻³⁴ 3 10⁸/405 10⁻⁹  -1.424 10⁻¹⁹

           Ф = 4.911 10⁻¹⁹ - 1.424 10⁻¹⁹

           Ф = 3.4571 10⁻¹⁹ J

         

we reduce to eV

           Ф = 3.4871 10⁻¹⁹ J (1 eV / 1.6 10⁻¹⁹ J)

           Ф = 2.179 eV

4 0
2 years ago
That which flows on uniformly, of which a day is a logical portion, is called time. True or False
mr_godi [17]
The answer to the statement is true because the day is of the logical proportion it has to be time.
3 0
3 years ago
Read 2 more answers
Find the total electric charge of 1.7 kg of electrons. me=9.11×10−31kg, e=1.60×10−19C.
Gelneren [198K]

Answer:

2.99\cdot 10^{11}C

Explanation:

The mass of one electron is

m_e = 9.11\cdot 10^{-31}kg

So the number of electrons contained in M=1.7 kg of mass is

N=\frac{M}{m_e}=\frac{1.7 kg}{9.11\cdot 10^{-31}kg}=1.87\cdot 10^{30}

The charge of one electron is

e=1.60\cdot 10^{-19} C

So, the total charge of these electrons is equal to the charge of one electron times the number of electrons:

Q=Ne=(1.87\cdot 10^{30})(1.6\cdot 10^{-19}C)=2.99\cdot 10^{11}C

8 0
3 years ago
Please help! thank you​
BlackZzzverrR [31]

Answer:

poor, too precise

good

good

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Explanation:

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