While falling, both the sheet of paper and the paper ball experience air resistance. But the surface area of the sheet is much more than that of the spherical ball. And air resistance varies directly with surface area. Hence the sheet experiences more air resistance than the ball and it falls more slowly than the paper ball.
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The work done by the machine is equal to the product between the force applied and the distance over which the force is applieds, so in this case:

And the power of the machine is equal to the ratio between the work done by the machine and the time taken:
Answer: B
Explanation:
You can use the conservation of momentum, under the assumption that no mass was lost when the collision occurred. The initial momentum of the system must equal the final momentum of the system. Our system is the region including, and only including, the satellite and the space debris. Classical momentum is defined as the product of mass and velocity:


Due to mass 1 equaling mass 2, we can factor these quantities out:

Cancel the mass term on both sides to get:

We have the initial and final velocities for everything besides the final velocity of the satellite. Plug everything in:

