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charle [14.2K]
3 years ago
9

An ice sled powered by a rocket engine starts from rest on a large frozen lake and accelerates at 12.8 m/s2 . At t1 the rocket e

ngine is shut down and the sled moves with constant velocity v for another t2 s. The total distance traveled by the sled is 5.37 × 103 m and the total time is 97.7 s. Find t1.
Physics
1 answer:
Simora [160]3 years ago
5 0

Answer:4.39 s

Explanation:

Given

initial velocity u=0

acceleration a=12.8 m/s^2

velocity acquired by sled in t_1 time

v=0+at

v=12.8t_1

distance traveled by sled in t_1 s

v^2-u^2=2as

(12.8t_1)^2-0=2\times 12.8\times s_1

s_1=6.4\cdot t_1^2

distance traveled in t_2 time with velocity v=12.8t_1

s_2=v\times t_2

s_2=12.8\times t_1\times t_2

s_2=12.8\cdot t_1\cdot t_2

s_1+s_2=5.37\times 10^3

6.4t_1^2+12.8t_1t_2=5370----1

t_1+t_2=97.7 s

t_2=97.7-t_1

substitute the value of t_2 in 1

we get

6.4t_1^2-1250.56t_1+5370=0

thus t_1=\frac{1250.56-1194.33}{12.8}=4.39 s

t_1=4.39 s

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