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hichkok12 [17]
2 years ago
5

Can anyone pls help? (fill in the blank)

Chemistry
1 answer:
masya89 [10]2 years ago
3 0

Answer:

reactivity:very reactive,less reactive

density:float in water,sink in water

melting and boiling point:low,high

colour of salts: colourless,often coloured

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How many mL of 2M stock solution would I use to prepare 0.500 L of 0.1 M NaCl?
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Answer:

25 mL

Explanation:

Step 1: Given data

  • Concentration of the concentrated solution (C₁): 2 M
  • Volume of the concentrated solution (V₁): ?
  • Concentration of the diluted solution (C₂): 0.1 M
  • Volume of the diluted solution (V₂): 0.500 L

Step 2: Calculate the volume of the concentrated NaCl solution

We will use the dilution rule.

C₁ × V₁ = C₂ × V₂

V₁ = C₂ × V₂ / C₁

V₁ = 0.1 M × 0.500 L / 2 M

V₁ = 0.025 L = 25 mL

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