Answer:
This stiffening process, called Rigor Mortis, has a roughly known time of occurrence and can therefore be used to estimate time of death. In general: If the body feels warm and no rigor is present, death occurred under 3 hours before. If the body feels warm and stiff, death occurred 3-8 hours earlier.
Answer:
2
Explanation:
so let say 5.0/100×40
that is 2
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Answer:
The partial pressure of the
in the final mixture is 200 kPa.
Explanation:
Pressure of nitrogen gas when the two tanks are disconnected = 500 kPa
Pressure of the carbon-dioxide gas when the two tanks are disconnected = 200 kPa
Moles of nitrogen gas =
Moles of carbon dioxide gas =
After connecting both the tanks:
The total pressure of the both gasses in the tank = p = 250 kPa
According to Dalton' law of partial pressure:
Total pressure is equal to sum of partial pressures of all the gases
Partial pressure of nitrogen =
Partial pressure of carbon dioxide=




The partial pressure of the
in the final mixture is 200 kPa.
the equilibrium concentration of H₂(g) at 700°C = 0.00193 mol/L
0.00193 mol/L
Given that:
numbers of moles of H₂S = 0.59 moles
Volume = 3.0-L
Equilibrium constant = 9.30 × 10⁻⁸
The equation for the reaction is given as :
2H₂S ⇄ 2H₂(g) + S₂(g)
The initial concentration of H₂S =
The initial concentration of H₂S =
= 0.1966 mol/L
The ICE table is shown be as :
2H₂S ⇄ 2H₂(g) + S₂(g)
Initial 0.9166 0 0
Change -2 x +2 x + x
Equilibrium (0.9166 - 2x) 2x x
(since 2x < 0.1966 if solved through quadratic equation)
The equilibrium concentration for H₂(g) = 2x
∴
= 0.00193 mol/L
Thus, the equilibrium concentration of H₂(g) at 700°C = 0.00193 mol/L
To know more about equilibrium concentration
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