Answer:
M g H / 2 = M g L / 2 initial potential energy of rod
I ω^2 / 2 = 1/3 M L^2 * ω^2 / 2 kinetic energy attained by rod
M g L / 2 = 1/3 M L^2 * ω^2 / 2
g = 3 L ω^2
ω = (g / (3 L))^1/2
Answer:
The distance traveled in 1 year is:
Explanation:
Given
--- speed
--- time
Required
The distance traveled
This is calculated as:

So, we have:

This gives:


-- approximated
A particle smaller than an atom or a <span>cluster of such particles </span>
Time period = time/no. of waves = 6/3 = 2s