Tarzan swings on a 30.0m long vine initially inclined at an angle 37 degrees with the vertical. What is his speed at the bottom
1 answer:
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Distance (s)=100m
time
T₁=10
T₂=10.2
T₃=10.4
T₄=10.6
by v=
we get
V₁=
V₁=10m/s
V₂=
V₂=9.8m/s
V₃=
V₃=9.61 m/s
V₄=
V₄=9.43 m/s
V₁:V₂:V₃:V₄ = 10 : 9.8 : 9.61 : 9.43
time
T₁=10
T₂=10.2
T₃=10.4
T₄=10.6
by v=
we get
V₁=
V₁=10m/s
V₂=
V₂=9.8m/s
V₃=
V₃=9.61 m/s
V₄=
V₄=9.43 m/s
V₁:V₂:V₃:V₄ = 10 : 9.8 : 9.61 : 9.43