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sasho [114]
4 years ago
14

A rod of 2.0-m length and a square (2.0 mm X 2.0 mm) cross section is made of a material with a resistivity of 6.0 E–8 Ohm meter

. If a potential difference of 0.50 V is placed across the ends of the rod, at what rate is heat generated in the rod? *
Physics
1 answer:
Alex Ar [27]4 years ago
4 0

Answer:

8.33*10^-16 Watt

Explanation:

Given that

Length of the rod, l = 2 m,

Area of the rod, A = 2 x 2 mm² = 4*10^-6 m²

resistivity of the rod, p = 6*10^-8 ohm metre,

Potential difference of the rod, V = 0.5 V

Let R be the resistance of the rod, then

R = p * l / A

R = (6*10^-8 * 2) / (4*10^-6)

R = 3*10^14 ohm

Heat generated per second = V² / R Heat = (0.5)² / (3*10^14)

Heat = 0.25 / 3*10^14

Heat = 8.33*10^-16 Watt

Therefore, the rate at which heat is generated is 8.33*10^-16 Watt

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wallace and vernonville are 192 miles apart. A car leaves wallace traveling towards vernonville, and another car leaves vernonvi
Anastaziya [24]
 <span>1 hour 36 minutes = 1 36/60 = 1 3/5 = 1.6 hours 

Speed of car leaving wallace be x mph 

Speed of car leaving vernonville will be ( x+10) mph 

1.6 ( x + x+10) = 192

2x + 10 = 120

2x = 110

x = 55

ANSWER Wallace car = 55 mph Vernonville = 65mph 

Therefore, </span><span>the average speeds of both cars are 55 mph for the Wallace car and 65 mph for the Vernonville.


I hope my answer has come to your help. Thank you for posting your question here in Brainly.</span>
3 0
3 years ago
A person uses a constant force to push a 14.0 kg crate 1.80 m up a frictionless 10⁰ incline and to also increase its speed from
zubka84 [21]

a) Making h as the shorter cathetus, we have,

h=1.8*sin10=0.312

We proceed to calculate the work done by gravity

W_g=-mgh

W_g=-140*0.312=-43.76J

b) It's necessary to calculate the Kinetic Energy, we use the equation of KE,

\Delta KE = \frac{1}{2}m(v_2^2-v_1^2)

\Delta KE = \frac{1}{2}14(1.5^2-0.5^2)=14J

c) By work energy theorem

W_{net}=\Delta KE \rightarrow W_net = 14J

d) we calculate net work through the law of conservation

W_{net}=W_f+W_g=14

\rightarrow W_f = 14-W_g=14-(-43.76)

W_f=57.76J

6 0
3 years ago
Why do electrons rather than protons make up the flow of charge in a metal wire?
andrew-mc [135]
Protons are tightly bound to the nucleus of atoms, and the nucleus is
'shielded' from the outside world by the 'cloud' of electrons around it. 
It takes a lot of energy to separate a proton from the nucleus.  When
that happens, it's a 'radioactive' or a 'nuclear' event, and the atom has
changed into an atom of a different substance.  This isn't something
that's happening around us very often.

On the other hand, the electrons are on the outside of the atom, and
it's rather easy to convince an electron to leave its atom and flow off
to somewhere else.
6 0
3 years ago
. Are there human health risks from exposure (or overexposure) to X-rays? If so:
algol [13]
<h3>yes, there are human health risks caused by exposure to x rays</h3>
  • describe the main risk (s) ::: - may cause damage to cells in the body

                                                      - large doses may lead cells to be cancerous        

                                                      - causes mutations in the DNA

  • describe common sources of exposure ( or overexposure ) :::

           - natural background radiation   e.g. - cosmic rays

           - medical radiation   e.g. - CT scans & medical x - rays

           - man - made radiation   e.g. - airport security scanners

  • describe a technology, device, or behavior that can be used for protection, or to decrease exposure :::

          - x - ray beam filters

          - digital x - ray detectors

          - technologies reduce radiation doses in radiography &  

            mammography

<em>hope that helps !!</em>

3 0
3 years ago
Read 2 more answers
Two forces are acting on an object as shown in Fig. on the right. What is the magnitude of the resultant force?
svetlana [45]

Answer:

185 N

Explanation:

Sum of forces in the x direction:

Fₓ = -(80 N cos 75°) + (120 N cos 60°)

Fₓ = 39.3 N

Sum of forces in the y direction:

Fᵧ = (80 N sin 75°) + (120 N sin 60°)

Fᵧ = 181.2 N

The magnitude of the net force is:

F = √(Fₓ² + Fᵧ²)

F = √((39.3 N)² + (181.2 N)²)

F = 185 N

8 0
3 years ago
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