A rod of 2.0-m length and a square (2.0 mm X 2.0 mm) cross section is made of a material with a resistivity of 6.0 E–8 Ohm meter
1 answer:
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Answer:
3%
Explanation:
The total energy ingested is 3000J and of those 3000J, 100J are used for growth and reproduction, this is the part of production in the porcupine, since the other 800J and 2100J are used for internal processes of the porcupine.
Therefore the production efficiency is 100J of the 3000J, let's find out how much it is in percentage:
⇒0.033=3.3% ≈ 3%
The correct option es 3% of production efficiency.
Answer:
2.67kg
Explanation:
The maximum velocity, of a body experiencing simple harmonic motion is given by equation (1);
where is the angular velocity and A is the amplitude.
The problem describes the oscillation of a loaded spring, and for a loaded spring the angular velocity is given by equation (2);
where k is the force constant of the spring and m is the loaded mass.
We can make the subject of formula in equation (1) as follows;
We then combine equations (2) and (3) as follows;
According to the problem, the following are given;
We then substitute these values into equation (4) and solve for the unknown mass m as follows;
Squaring both sides, we obtain the following;
The distance of the sound from the tuba is 4.82 m.
<h3>Area of the tube</h3>
The area of the tuba is calculated as follows;
I = P/A
where;
- I is intensity of sound
- P is power
- A is area
A = P/I
A = 0.35 / (1.2 x 10⁻³)
A = 291.67 m²
<h3>Distance of the sound</h3>Area = 4πr²
Thus, the distance of the sound from the tuba is 4.82 m.
Learn more about intensity of sound here: brainly.com/question/4431819